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lorasvet [3.4K]
3 years ago
11

IM GIVING BRAINLIEST PLEASE HELP!!!

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
4 0

Answer:

B. Distribute

Step-by-step explanation:

The first step is to apply the distributive property.

Please let me know if I was correct

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Convert 16.7 inches to yards
vagabundo [1.1K]
16.7 inches is 0.464 yards
6 0
3 years ago
Write the equation of the line in slope intercept form that goes through the points (5, 8) and (6,5)
Bingel [31]
Okay so first plug this in
8-5
——
5-6

3/-1

-3

Slope= -3

y=-3x+b

Next, plug in one of the points to find b.

5=-3(6)+b
5=-18+b
+18 +18
—————
23=b

y=-3x+23

Hope this helps!!
5 0
4 years ago
What values from the set {10, 11, 12, 13} that makes the equation 2(× - 5) = 12 true is, , 10, 11, 12 or 13?
olasank [31]

Answer: The value necessary from the set to make the equation true was 11.


Step-by-step explanation:

Process of elimination:

1. 2([10]-5)

= 2(5)

= 10, not 12.

2. 2([11]-5)

= 2(6)

= 12; the answer we need.

We substituted x for 11, and then the equation worked; so therefore the value we needed from the set was 11.


4 0
3 years ago
50 pts pls help <br> What is the range of the function shown on the graph above?
zubka84 [21]
572^ the answer above is correct!!!!!
5 0
3 years ago
Read 2 more answers
The table shows the results of a random survey at Scobey Middle School about students’ favorite cookies. Based on the results fr
Vinil7 [7]

Given:

Random survey of Scobey middle school

To find:

The percent of students like cookies.

Solution:

Total number of cookies = 49 + 12 + 10 + 8 + 3

                                         = 82

Percentage formula:

$\text{Percentage of part} = \frac{\text{Part}}{\text{Whole} }\times 100

$\text{Chocolate chip }\%=\frac{49}{82}\times100

                            = 59.76%

Percent of student like chocolate chip is 59.76%.

$\text{Peanut butter}\%=\frac{12}{82}\times100

                          = 14.64%

Percent of student like peanut butter is 14.64%.

$\text{Oatmeal}\%=\frac{10}{82}\times100

                = 12.19%

Percent of student like oatmeal is 12.19%.

$\text{Sugar}\%=\frac{8}{82}\times100

             = 9.76%

Percent of student like sugar is 9.76%.

$\text{Raisin}\%=\frac{3}{82}\times100

             = 3.65%

Percent of student like raisin is 3.65%.

3 0
3 years ago
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