Question

A spinner has 5 equally sized sections, 2 of which are gray and 3 of which are blue. The spinner is spun twice. What is the probability that the first spin lands on gray and the second spin lands on blue ?

Answer 1

Answer:

6/25

Step-by-step explanation:

P(gray) = 2/5

P(blue) = 3/5

P(1st gray & 2nd blue) = (2/5)*(3/5) = 6/25

As the question already indicated the sequence, so no combination (nCr) should be considered.