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amm1812
3 years ago
14

Which of the following patterns or images could best be described by a translation?

Mathematics
1 answer:
babunello [35]3 years ago
6 0
Translations are all about shifting the same thing.
A is more of a rotation
C is more of an enlargement
D is a mere reflection of what's on the other side.

The pattern or image that could best be described by a translation is (B) <span>seats on a school bus</span>
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cricket20 [7]

Sorry, I won't understand

6 0
3 years ago
A triangle has an area of 14 square units. Its height is 7 units. What is the length of its base?
navik [9.2K]
The base should be 4. 
Area=1/2* b *h
4*7=28/2=14. 
3 0
3 years ago
Which inequality is represented by the graph y&gt;-2/3x+1 y&lt;-2/3x+1 y&lt;-3/2x+1 y&gt;-3/2x+1
soldi70 [24.7K]

Answer:

the 3rd one is the graph answer

6 0
3 years ago
At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper
Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that p = 0.3

14 of these containers of paper.

This means that n = 14

What is the probability that John finds less than 7 golden sheets of paper?

P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068

P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407

P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134

P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943

P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290

P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963

P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262

P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067

90.67% probability that John finds less than 7 golden sheets of paper

7 0
3 years ago
Suppose that only 25% of all drivers come to a complete stop at an intersection having flashing red lights in all directions whe
Juliette [100K]

Answer:

X \sim Binom(n=15, p=0.25)

For this case we can use the probability mass function and we got:

P(X= 5) = (15C5) (0.25)^{5} (1-0.25)^{15-5}= 0.165

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=15, p=0.25)

For this case we can use the probability mass function and we got:

P(X= 5) = (15C5) (0.25)^{5} (1-0.25)^{15-5}= 0.165

5 0
3 years ago
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