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2 years ago

An oblique triangular pyramid has a base area

1 answer:

5 0

The height of the oblique triangular pyramid is 18 units if the base area of 21 square units and a volume of 126 cubic units.

<h3>What is volume?</h3>

It is defined as a three-dimensional space enclosed by an object or thing.

We know the volume of an oblique triangular pyramid is given by:

$\rm V = \dfrac{1}{3}b\times h$

Where b is the area of the base and h is the height of the pyramid.

We have b = 21 square units and V = 126 cubic units.

$\rm 126 = \dfrac{1}{3}\times21\times h$

h = 18 units

Thus, the height of the oblique triangular pyramid is 18 units if the base area of 21 square units and a volume of 126 cubic units.

Learn more about the volume here:

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sergeinik [125]

Answer:

26 miles

Step-by-step explanation:

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3 years ago

She made 76,450 last year she received a 4% salary increase how much does she make now ?

Luden [163]

Answer:

$79,508

Step-by-step explanation:

Change 4% to decimal form: drop the percent sign replacing it with a decimal

point then move the decimal point two places to

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Salary increase: $76,450 x .04 = $3,058

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3 years ago

The number of typing errors made by a typist has a Poisson distribution with an average of three errors per page. If more than t

damaskus [11]

Answer:

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Poisson distribution with an average of three errors per page

This means that $\mu = 3$

What is the probability that a randomly selected page does not need to be retyped?

Probability of at most 3 errors, so:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498$

$P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494$

$P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240$

$P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240$

Then

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0498 + 0.1494 + 0.2240 + 0.2240 = 0.6472$

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

3 0

2 years ago

How do you solve this 5b-28>27

damaskus [11]

B>11 hope this helps :)

8 0

3 years ago

Round 3.73 to the nearest whole number

julsineya [31]

3.73 rounded to the nearest whole number would be 4

7 0

3 years ago