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3 years ago

What is the volume of the pyramid

Mathematics

1 answer:

Marianna [84]3 years ago

3 0

For this case we have by definition, that the volume of a square base pyramid is given by:

$V = \frac {1} {3} * L ^ 2 * h$

Where:

L: It's the side of the base (square side)

h: It's the height of the pyramid

Substituting:

$L = 6 \ ft\\h = 10 \ ft$

$V = \frac {1} {3} * (6) ^ 2 * 10\\V = \frac {1} {3} * 36 * 10\\V = 120 \ ft ^ 3$

Answer:

$V = 120 \ ft ^ 3$

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HELPPPPP PLEWSE POINT SLOPE FORMULA

Sergio039 [100]

Answer:

y = -3/4(x+4)

Step-by-step explanation:

The point slope formula is given by

y-y1 = m(x-x1)

where m is the slope and (x1,y1) is a point on the line

y-0 = -3/4(x - -4)

y = -3/4(x+4)

7 0

3 years ago

Read 2 more answers

Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm

Vlad1618 [11]

Answer:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar x =512$ represent the sample mean

$\sigma=100$ represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

$Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

$25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}$

And we can find the critical value $z_{\alpha/2}$ like this:

$z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576$

And we know that on the right tail of the z score =2.576 we have $\alpha/2$ of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998= $\alpha/2$ , so then $\alpha=0.00498*2=0.009995 \approx 0.01$ , and then we can find the confidence like this: