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3 years ago

9

ASAPPP HURRY UP PLSSS

2 answers:

astraxan [27]3 years ago

8 0

Answer:

12

Step-by-step explanation:

professor190 [17]3 years ago

5 0

Answer:

12

Step-by-step explanation:

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Log(5) + log(3) rewrite the following in the form log(c).

Dennis_Churaev [7]

Log (5) + log (3) = log (15)

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3 years ago

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When you divide with negative exponents, you divide the rational numbers like normal and then you add the exponents.

Doss [256]

Answer:

the same as multiplying them, except you're doing the opposite: subtracting where you would have added and dividing where you would have multiplied. If the bases are the same, subtract the exponents. Remember to flip the exponent and make it positive, if needed.

Step-by-step explanation:

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2 years ago

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3/8, -2 , 34% , -4/9 from least to greatest

Whitepunk [10]

-2, -4/9 , 34%, 3/8. This is your answer

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3 years ago

Simplify 16m6-15mn+m6+17mn

tia_tia [17]

Answer:

$17m^6 + 2mn$

Step-by-step explanation:

$16m^6 -15mn +m^6 + 17mn$

Combine like terms, rewrite the equation and perform the operations between the coefficients,

$16m^6 +m^6 -15mn+17mn$

$17m^6 + 2mn$

3 0

2 years ago

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Evaluate the variable expression when a=-4, b=2, c=-3, and d =4. b-3a/bc^2-d

gtnhenbr [62]

Answer:

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

$\dfrac{b-3a}{bc^{2}-d}=1$

Step-by-step explanation:

Evaluate:

$\dfrac{b-3a}{bc^{2}-d}$

When a=-4, b=2, c=-3, and d =4

Solution:

Substitute, a=-4, b=2, c=-3, and d =4 in above expression we get

$\dfrac{b-3a}{bc^{2}-d}=\dfrac{2-3(-4)}{2(-3)^{2}-4}\\\\=\dfrac{2+12}{18-4}\\\\$

$\dfrac{b-3a}{bc^{2}-d}=\dfrac{14}{14}=1$

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

$\dfrac{b-3a}{bc^{2}-d}=1$

6 0

3 years ago