Using pythagorean identities,tan(sin^-1(-5/13))= tan(arcsin(-5/13))
Let A = arcsin(-5/13) = -arcsin(5/13)
Thus, sin A = -5/13 and cos A = sqrt(1 - (5/13)^2) = 12/13.= tan(A)= sin(A) / cos(A)= -5/13 / (12/13)= -5/12
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Answer:
3
Step-by-step explanation:
i would say 3 different ways because 4 x 3 = 12
Hope this helps!
The slope of the inverse is 1/2.
The degree of a polynomial is the largest exponent on the variable.
For the given problem there is only one term with an exponent: 5x^2.
The exponent is 2, so the degree would be 2.
