All categories

2 years ago

There are 5 numbers, they are- 5,8,2,9,10

Mathematics

1 answer:

Crank2 years ago

8 0

Answer:

Mean: 6.8

Median: 2

Mode: There is no mode of the data set

Step-by-step explanation:

Finding the mean: 5+8+2+9+10= 34 divided by the numbers of the data set which is 5= 6.8

Finding the median: The middle of the data set which is 2

Finding the mode: the most frequently occurring number which doesn't appear in this data set which means there is none.

You might be interested in

What is the point slope form of (7,-4) and (-1,3)

BaLLatris [955]

Answer:

y-3 = -7/8(x+1)

Step-by-step explanation:

The slope of a line given two points is given by

m = (y2-y1)/(x2-x1)

= (3 - -4)/(-1 -7)

= (3+4) / (-1-7)

= 7/ -8

= -7/8

The point slope form of a line is

y-y1 = m(x-x1)

y - 3 = -7/8( x - -1)

y-3 = -7/8(x+1)

5 0

2 years ago

Read 2 more answers

Michelle receives 32K per year as an assistant fast food manager. Her benefits include health insurance, paid holidays, retireme

ryzh [129]

Answer:

The annual salary of Michelle including benefits = $48, 440

Step-by-step explanation:

<em>Since, you have not specified the table to show the value of each benefit.</em>

<em>So, I am assuming this table as the reference table to show the value of each benefit.</em>

<h3 /><h3><u>Benefits Value Table:</u></h3>

<h2> Benefit Value</h2>

Health Insurance $7,550

Paid Holidays $660

Retirement Contributions $4,500

Paid Vacation $1,230

Uniform Supplied $2,500

Here are the benefits details from the table:

Michelle receiving per year without benefits = $32000

Health Insurance as benefit = $7,550

Paid Holidays as benefit = $660

Retirement Contributions as benefit = $4,500

Paid Vacation as benefit = $1,230

Uniform Supplied as benefit = $2,500

So, the amount she gets from benefits = $7,550 + $660 + $4,500 + $1,230 + $2,500 = $16,440

So, the annual salary, including benefits could be calculated as:

Michelle receiving per year without benefits = $32000

The amount Michelle gets from benefits = $16,440

Michelle have annual salary including benefits = $32000 + $16,440

= $48, 440

Hence, the annual salary of Michelle including benefits = $48, 440

Keywords: calculation, salary, benefits, saving

Learn more about salary calculation from brainly.com/question/5715627

#learnwithBrainly

8 0

2 years ago

The large square below has a side length of 8 inches, and the smaller white square inside the large square has a side length of

9966 [12]

The image is not attached with, but by reading the question it is obvious that the blue region lies inside the larger square and outside the smaller square. That is the region between the two squares is the blue region.

We know the dimensions of both squares, using which we can find the area of both squares. Subtracting the area of smaller square from larger one, we can find the area of blue square and further we can find the said probability.

Area of larger square = 8 x 8 = 64 in²
Area of smaller square = 2 x 2 = 4 in²
Area of blue region = 64 - 4 = 60 in²

The probability that a randomly chosen point lies within the blue region = Area of blue region/Total area available

Therefore, the probability that a point chosen at random is in the blue region = 60/64 = 0.9375

7 0

2 years ago

Read 2 more answers

Under his cell phone plan, Liam pays a flat cost of $69.50 per month and $5 per gigabyte. He wants to keep his bill under $90 pe

natulia [17]

Answer:

5y+69.50<90

Step-by-step explanation:

You can think of the number of gigabytes he will use as "y", since we don't know the number of gigabytes he will use. The flat cost of one month is $69.50.

You need to add those to calculate the complete cost. The inequality would use a less than sign because he needs to pay less than $90/month. It would not use an inequality sign with a line under it because the problem doesn't say he wants to use $90 or less.

You would solve using basic computation (subtraction and division). Hope this helped!

3 0

1 year ago

Solve the system of equations.<br><br><br><br> −2x+5y =−35<br> 7x+2y =25

Otrada [13]

Answer:

The equations have one solution at (5, -5).

Step-by-step explanation:

We are given a system of equations:

$\displaystyle{\left \{ {{-2x+5y=-35} \atop {7x+2y=25}} \right.}$

This system of equations can be solved in three different ways:

Graphing the equations (method used)
Substituting values into the equations
Eliminating variables from the equations

<u>Graphing the Equations</u>

We need to solve each equation and place it in slope-intercept form first. Slope-intercept form is $\text{y = mx + b}$ .

Equation 1 is $-2x+5y = -35$ . We need to isolate y.

$\displaystyle{-2x + 5y = -35}\\\\5y = 2x - 35\\\\\frac{5y}{5} = \frac{2x - 35}{5}\\\\y = \frac{2}{5}x - 7$

Equation 1 is now $y=\frac{2}{5}x-7$ .

Equation 2 also needs y to be isolated.

$\displaystyle{7x+2y=25}\\\\2y=-7x+25\\\\\frac{2y}{2}=\frac{-7x+25}{2}\\\\y = -\frac{7}{2}x + \frac{25}{2}$

Equation 2 is now $y=-\frac{7}{2}x+\frac{25}{2}$ .

Now, we can graph both of these using a data table and plotting points on the graph. If the two lines intersect at a point, this is a solution for the system of equations.

The table below has unsolved y-values - we need to insert the value of x and solve for y and input these values in the table.

$\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & a \\ \cline{1-2} 1 & b \\ \cline{1-2} 2 & c \\ \cline{1-2} 3 & d \\ \cline{1-2} 4 & e \\ \cline{1-2} 5 & f \\ \cline{1-2} \end{array}$

$\bullet \ \text{For x = 0,}$

$\displaystyle{y = \frac{2}{5}(0) - 7}\\\\y = 0 - 7\\\\y = -7$

$\bullet \ \text{For x = 1,}$

$\displaystyle{y=\frac{2}{5}(1)-7}\\\\y=\frac{2}{5}-7\\\\y = -\frac{33}{5}$

$\bullet \ \text{For x = 2,}$

$\displaystyle{y=\frac{2}{5}(2)-7}\\\\y = \frac{4}{5}-7\\\\y = -\frac{31}{5}$

$\bullet \ \text{For x = 3,}$

$\displaystyle{y=\frac{2}{5}(3)-7}\\\\y= \frac{6}{5}-7\\\\y=-\frac{29}{5}$

$\bullet \ \text{For x = 4,}$

$\displaystyle{y=\frac{2}{5}(4)-7}\\\\y = \frac{8}{5}-7\\\\y=-\frac{27}{5}$

$\bullet \ \text{For x = 5,}$

$\displaystyle{y=\frac{2}{5}(5)-7}\\\\y=2-7\\\\y=-5$

Now, we can place these values in our table.

As we can see in our table, the rate of decrease is $-\frac{2}{5}$ . In case we need to determine more values, we can easily either replace x with a new value in the equation or just subtract $-\frac{2}{5}$ from the previous value.

For Equation 2, we need to use the same process. Equation 2 has been resolved to be $y=-\frac{7}{2}x+\frac{25}{2}$ . Therefore, we just use the same process as before to solve for the values.

$\bullet \ \text{For x = 0,}$

$\displaystyle{y=-\frac{7}{2}(0)+\frac{25}{2}}\\\\y = 0 + \frac{25}{2}\\\\y = \frac{25}{2}$

$\bullet \ \text{For x = 1,}$

$\displaystyle{y=-\frac{7}{2}(1)+\frac{25}{2}}\\\\y = -\frac{7}{2} + \frac{25}{2}\\\\y = 9$

$\bullet \ \text{For x = 2,}$

$\displaystyle{y=-\frac{7}{2}(2)+\frac{25}{2}}\\\\y = -7+\frac{25}{2}\\\\y = \frac{11}{2}$

$\bullet \ \text{For x = 3,}$

$\displaystyle{y=-\frac{7}{2}(3)+\frac{25}{2}}\\\\y = -\frac{21}{2}+\frac{25}{2}\\\\y = 2$

$\bullet \ \text{For x = 4,}$

$\displaystyle{y=-\frac{7}{2}(4)+\frac{25}{2}}\\\\y=-14+\frac{25}{2}\\\\y = -\frac{3}{2}$

$\bullet \ \text{For x = 5,}$

$\displaystyle{y=-\frac{7}{2}(5)+\frac{25}{2}}\\\\y = -\frac{35}{2}+\frac{25}{2}\\\\y = -5$

And now, we place these values into the table.

$\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}$

When we compare our two tables, we can see that we have one similarity - the points are the same at x = 5.

Equation 1 Equation 2

$\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}$ $\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}$

Therefore, using this data, we have one solution at (5, -5).

4 0

3 years ago