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2 years ago

Please help :(((

Mathematics

1 answer:

Usimov [2.4K]2 years ago

4 0

The answer is table B and graph A !!

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Lionel plays trumpet for a minimum of 45 minutes on the days that he practices. If x is the number of days that Lionel practices

Angelina_Jolie [31]

Answer:

The inequality is $0.75x\geq y$

Step-by-step explanation:

Given : Lionel plays trumpet for a minimum of 45 minutes on the days that he practices. If x is the number of days that Lionel practices and y is the total number of hours he spends practicing.

To find : Which inequality represents this situation?

Solution : He plays trumpet for a minimum of 45 minutes

$45 \text{minutes}=\frac{45}{60}=\frac{3}{4}=0.75\text{hours}$

If x is the number of days that Lionel practices then he practices for at least

$=0.75x$ hours

y is the total number of hours he spends practicing

So, the inequality form is:

$0.75x\geq y$

i.e, 0.75x is greater than y.

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4 years ago

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Feliz [49]

Answer:

Length: 3w-4

Step-by-step explanation:

Length: 3w-4

Width: W

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Using the laws of indices simplify 625^3/8 ×5^1/2÷ 25

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Answer:

Step-by-step explanation:

$\huge {625}^{ \frac{3}{8} } \times {5}^{ \frac{1}{2} } \div 25 \\ \\ = \huge {( {5}^{4})}^{ \frac{3}{8} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ = \huge{5}^{ \cancel4 \times \frac{3}{ \cancel8 \: \: \red{ \bold 2}} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ \frac{3}{2} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ \frac{3}{2} + \frac{1}{2}} \div {5}^{2} \\ \\ \huge= {5}^{ \frac{4}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ 2 } \div {5}^{2} \\ \\ \huge= {5}^{ 2 - 2 } \\ \\ \huge= {5}^{ 0 } \\ \\ \huge= 1$

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Answer:

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Step-by-step explanation:

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