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Svet_ta [14]
2 years ago
5

Show that: (p¼- q¼)(p¼ + q¼)(√P+√q)= p-q.​

Mathematics
2 answers:
Naily [24]2 years ago
4 0

Answer:

See below ~

Step-by-step explanation:

Identity used :

  • (a - b)(a + b) = a² - b²

Simplifying the LHS :

  • (p¼ - q¼)(p¼ + q¼)(√p + √q)
  • (√p - √q)(√p + √q)
  • p - q
  • Equal to the RHS

∴ Hence, it is proved √

Irina18 [472]2 years ago
3 0

Answer:

Step-by-step explanation:

let p¼ = a, q¼ = b

L.H.S. = (a - b)(a + b)(a² + b²) = (a² - b²)(a² + b²) = (a²)² - (b²)² = p - q = R.H.S.

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Answer:

<u>Complete table of values</u>

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Step-by-step explanation:

Given;

y = 2x² + 2x - 3

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y:    1          -3       -3          1         9

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