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1 year ago

Show that: (p¼- q¼)(p¼ + q¼)(√P+√q)= p-q.

Mathematics

2 answers:

Naily [24]1 year ago

4 0

Answer:

See below ~

Step-by-step explanation:

Identity used :

(a - b)(a + b) = a² - b²

Simplifying the LHS :

(p¼ - q¼)(p¼ + q¼)(√p + √q)
(√p - √q)(√p + √q)
p - q
Equal to the RHS

∴ Hence, it is proved √

Irina18 [472]1 year ago

3 0

Answer:

Step-by-step explanation:

let p¼ = a, q¼ = b

L.H.S. = (a - b)(a + b)(a² + b²) = (a² - b²)(a² + b²) = (a²)² - (b²)² = p - q = R.H.S.

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2 years ago

A tube feeding formula contains 6 grams of protein per each 80 ml of the formula. If the patient needs 120 grams of protein per

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Answer:

1600 ml.

Step-by-step explanation:

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3 years ago

What is the equation of the graph below?

wlad13 [49]

Answer:

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Step-by-step explanation:

From the graph, we can see that y = -1 when x = 0.

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3 years ago

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2 years ago

How do I answer this question?

Novay_Z [31]

Due to the Triangle Angle Sum Theorem, we know that the sum of the interior angles of a triangle equals 180 degrees, therefore,

180 = m<1 + m<2 + m<3

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2 years ago

Show that: (p¼- q¼)(p¼ + q¼)(√P+√q)= p-q.​

Show that: (p¼- q¼)(p¼ + q¼)(√P+√q)= p-q.