PLS help, trig homework- will offer brainliest :)

Craig went bowling with $25 to spend. he rented shoes for $5.00 and paid $4.00 for each game. What was the greatest number of ga

Anton [14]

Answer: A

Step-by-step explanation:

Given:

Budget = $25

Shoes rental = $5.00

Price per game = $4.00

To find the greatest number of games he played...

↓

First, subtract the rent for the shoes from the budget.

25 - 5 = 20

Second, divide the remaining money or budget by the price per game.

20 ÷ 4 = 5 (greatest number of games played)

Lastly, check if the expense is the same as the original amount of money.

5 (shoes) + 4(5) (number of games played)

5 + 20 = 25 (original amount of money)

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4 0

2 years ago

Please help me. The original blueprint of the Moreno’s’ living room has a scale of 2 inches= 5 feet. The family wants to use a n

Svetradugi [14.3K]

Answer:

Part a) The scale of the new blueprint is $\frac{5}{8} \frac{in}{ft}$

Part b) The width of the living room in the new blueprint is $9.4\ in$

Step-by-step explanation:

we know that

The scale of the original blueprint is

$\frac{2}{5}\frac{in}{ft}$

and

the width of the living room on the original blueprint is 6 inches

so

<em>Find the actual width of the living room, using proportion</em>

$\frac{2}{5}\frac{in}{ft}=\frac{6}{x}\frac{in}{ft}\\ \\x=5*6/2\\ \\x=15\ ft$

<em>Find the actual length of the living room, using proportion</em>

$\frac{2}{5}\frac{in}{ft}=\frac{9.6}{x}\frac{in}{ft}\\ \\x=5*9.6/2\\ \\x=24\ ft$

<em>Find the scale of the new blueprint</em>, divide the length of the living room on the new blueprint by the actual length of the living room

$\frac{15}{24} \frac{in}{ft}$

simplify

$\frac{5}{8} \frac{in}{ft}$

<em>Find the width of the living room in the new blueprint, using proportion</em>

$\frac{5}{8}\frac{in}{ft}=\frac{x}{15}\frac{in}{ft}\\ \\x=15*5/8\\ \\x=9.4\ in$

3 0

3 years ago

The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation

Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

Sample size: n = 20
Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}$

This gives

$P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}$

$P(x = 11) = 0.0011$

Express as percentage

$P(x = 11) = 0.11\%$

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}$

This gives

$P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0$

$P(x = 20) = 0.0388$

Express as percentage

$P(x = 20) = 3.88\%$

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

$\mu = np$

So, we have:

$\mu = 20 \times 85\%$

$\mu = 17$

The standard deviation is calculated as:

$\sigma = np(1 - p)$

So, we have:

$\sigma = 20 \times 85\% \times (1 - 85\%)$

$\sigma = 20 \times 0.85 \times 0.15$

$\sigma = 2.55$

Hence, the mean and the standard deviation are 17 and 2.55, respectively.