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Natali5045456 [20]
2 years ago
7

write two equations that when graphed look like this *see image*. please help its due soon and i will give ya 75 points for answ

ering CORRECTLY thanks, 5 stars, and brainlist. Thank ya

Mathematics
1 answer:
Zigmanuir [339]2 years ago
8 0

The graph is showing the equation of circle x²+y²=4

<h3>What is a circle?</h3>

A circle is a two-dimensional geometry on the plane having a centre point and the circular line is drawn equidistant from the centre point.

The given graph in the question represents the equation of the circle cutting the points on the x-axis and y-axis at 4 which is the radius of the circle.

The equation will be as follows:-

x²+y²=4

Hence the graph is showing the equation of circle x²+y²=4

To know more about circles follow

brainly.com/question/24375372

#SPJ1

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3 years ago
Point Q' is the image of Q(5, -3) after a translation down 2 units and right 4 units. What are the coordinates of Q'?
ra1l [238]

Answer:

A. (9,-5)

Step-by-step explanation:

Translation down is -2 to the y coordinate, which is (5,-5). Then you translate it right 4 units, which is +4 to the x coordinate, so the final coordinate is (9,-5).

5 0
3 years ago
Choose Yes or No to tell whether each value of p is a solution for this inequality.
blsea [12.9K]
No
THE P IS SOMETHING U NEED TO PLUG IN
6 0
3 years ago
F(x)=x^2-5 and g(x)=3x+1 then f(g(2))
LuckyWell [14K]

Answer:

f(g(2)) = 44

Step-by-step explanation:

g(2) = 3(2) + 1 = 7

Plug 7 into f(x) since g(2) = 7

f(7) = 7² - 5 = 44

f(g(2)) = 44

8 0
3 years ago
A cardboard box without a lid is to be made with a volume of 4 ft 3 . Find the dimensions of the box that requires the least amo
Blababa [14]

Answer:

<h2><em>2ft by 2ft by 1 ft</em></h2>

Step-by-step explanation:

Total surface of the cardboard box is expressed as S = 2LW + 2WH + 2LH where L is the length of the box, W is the width and H is the height of the box. Since the cardboard box is without a lid, then the total surface area will be expressed as;

S  = lw+2wh+2lh ... 1

Given the volume V = lwh = 4ft³ ... 2

From equation 2;

h = 4/lw

Substituting into r[equation 1;

S = lw + 2w(4/lw)+ 2l(4/lw)

S = lw+8/l+8/w

Differentiating the resulting equation with respect to w and l will give;

dS/dw = l + (-8w⁻²)

dS/dw = l - 8/w²

Similarly,

dS/dl = w  + (-8l⁻²)

dS/dw = w - 8/l²

At turning point, ds/dw = 0 and ds/dl = 0

l - 8/w² = 0 and w - 8/l² = 0

l = 8/w²  and w =8/l²

l = 8/(8/l² )²

l = 8/(64/I⁴)

l = 8*l⁴/64

l = l⁴/8

8l = l⁴

l³ = 8

l = ∛8

l = 2

Hence the length of the box is 2 feet

Substituting l = 2 into the function l = 8/w² to get the eidth w

2 = 8/w²

1 = 4/w²

w² = 4

w = 2 ft

width of the cardboard is 2 ft

Since Volume = lwh

4 = 2(2)h

4 = 4h

h = 1 ft

Height of the cardboard is 1 ft

<em>The dimensions of the box that requires the least amount of cardboard is 2ft by 2ft by 1 ft</em>

8 0
3 years ago
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