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Makovka662 [10]
3 years ago
11

The magnitude, M, of an earthquake is defined to be M=log I/S, where I is the intensity of the earthquake (measured by the ampli

tude of the seismograph wave) and S is the intensity of a “standard” earthquake, which is barely detectable. What is the magnitude of an earthquake that is 10 times more intense than a standard earthquake? Use a calculator. Round your answer to the nearest tenth.
Mathematics
1 answer:
GarryVolchara [31]3 years ago
6 0

Answer:

<h2>1</h2>

Step-by-step explanation:

       Magnitude M of an earthquake is defined as M=log\text{ }\frac{I}{S}. Here I is the Intensity of the earthquake and  S is the intensity of standard earthquake.

       We have an earthquake that is 10 times more intense than a standard earthquake. Let us denote the intensity of the earthquake as I.

       10 times more intense than standard earthquake ⇒ I=10S

   Magnitude of the earthquake = M\text{ = }log\text{ }\dfrac{I}{S}\text{ = }log\text{ }\dfrac{10S}{S}\text{ = }log\text{ }10\text{ = }log_{10}\text{ }10\text{ = }1

∴ Magnitude of the earthquake is 1.

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Let's factorise it :

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\: {\qquad  \dashrightarrow \sf    {x}^{3} (x + 3) + [-5(x + 3)]  }

Using Distributive property we get :

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\: {\qquad  \dashrightarrow \sf    {x}^{3} +  {3x}^{3}   - 5x - 15 }

\: {\qquad  \dashrightarrow \sf    4{x}^{3}  - 5x - 15 }

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Therefore,

\: {\qquad  \dashrightarrow \sf   ( {x}^{3}   -  5)(x + 3)   =4{x}^{3}  - 5x - 15}

8 0
2 years ago
Based on the polynomial reminder theorem, what is the value of the function when x= -5
densk [106]

Answer:

-15

Step-by-step explanation:

Given is a polynomial in x

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Remainder theorem says that f(x) gives remainder R when divided by polynomial x-a means f(a) = R

Applying the above theorem we can say that value of the function when x =-5

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5 0
3 years ago
Read 2 more answers
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Marat540 [252]

Answer:

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3 years ago
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