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Usimov [2.4K]
3 years ago
14

Interest earned after 15 days on $8000, at 8.5%​

Mathematics
2 answers:
belka [17]3 years ago
8 0

Answer:

I=10,200

Step-by-step explanation:

I=PRT

P=8000

R=8.5

T=15 days

I=8000*0.085*15

I=10,200

DaniilM [7]3 years ago
4 0
200 maybe idk 1= 10 I got to do this so I can ask a question this is killing me
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\hat{p}_1-\hat{p}_2

and the standard deviation is given by

\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}

When np and n(1-p) is greater than 5, then the sampling distribution is approximately normal and we can use standard normal methods.

Thus, the propability of a test <span>for the difference between two population proportions is given by

P(X\ \textless \ x)=P\left(z\ \textless \  \frac{\hat{p}_1-\hat{p}_2}{\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}} \right)</span>
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There's a pair of points (3,5), (x,15) and a slope of 2 how do I find x​
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You have the slope and you have two points, so you can use the slope equation to find x.

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(1.1/1.2: Interpolating polynomials) Say we want to find a polynomialf(x) ofdegree 3,f(x) =a0+a1x+a2x2+a3x3,satisfying some inte
Hunter-Best [27]

(a) If

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then from the given conditions we get the system of equations,

<em>f</em> (-1) = <em>a</em>₀ - <em>a</em>₁<em> </em>+<em> a</em>₂ - <em>a</em>₃ = -1

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+ 4<em>a</em>₂ + 8<em>a</em>₃ = 1

<em>f</em> (3) = <em>a</em>₀ + 3<em>a</em>₁<em> </em>+<em> </em>9<em>a</em>₂ + 27<em>x</em> ³ = 5

(b) Similarly, if

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then

<em>f'(x)</em> = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ <em>x</em> + 3<em>a</em>₃ <em>x</em> ²

so that the given conditions yield the system,

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 0

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