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sveta [45]
2 years ago
5

="TexFormula1" title="{\boxed{\mathfrak\pink{\fcolorbox{pink}{pink}{Question}}}}" alt="{\boxed{\mathfrak\pink{\fcolorbox{pink}{pink}{Question}}}}" align="absmiddle" class="latex-formula">
7893 + 82 - 62\% =

Need Full Solution​
Mathematics
1 answer:
Naddika [18.5K]2 years ago
6 0

Answer:

First you would make 62% into \frac{62}{100}

7893+82-\frac{62}{100}

Than you would do 7893+82 which is 7975

7975-\frac{62}{100}

You would than simplify \frac{62}{100} which is \frac{31}{50}

7975- \frac{31}{50}

<u><em>Therefore your answer will be </em></u><em />\frac{398719}{50}<u><em> or in decimal form it will be </em></u><em />7974.38<em />

Hope that helps :>

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A lock consist of 4 dials where each dial has 6 letters what is the probability of guessing the right combination in one try’s
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Using it's concept, it is found that the probability of guessing the right combination in one try’s is of \frac{1}{1296}.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, there are 4 dials, each with a \frac{1}{6} probability of getting it correct, hence the probability of getting the right combination is given by:

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More can be learned about probabilities at brainly.com/question/14398287

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mel-nik [20]

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2xy\sqrt[3]{2x^2z} and 2xy(2x^2z)^{\frac{1}{3}}.

Step-by-step explanation:

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We have to simplify the above expression.

The above expression can be written as

\sqrt[3]{(2\times 8)(x^{3+2})y^3z}

\sqrt[3]{(2\times 2^3)(x^3\times x^2)y^3z}    [\because a^{m+n}=a^ma^n]

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2xy\sqrt[3]{2x^2z}    [\because \sqrt[n]{x^n}=x]

It can be written as exponent form.

2xy(2x^2z)^{\frac{1}{3}}    [\because \sqrt[n]{a}=a^{\frac{1}{n}}]

Therefore, the required expressions are 2xy\sqrt[3]{2x^2z} and 2xy(2x^2z)^{\frac{1}{3}}.

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I think the answer in this case would be D 
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Step-by-step explanation:

Look at middle of pot line

6 0
3 years ago
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