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postnew [5]
3 years ago
10

Solve for the variable: 3(x+2) - 9 = 15 - 4(5x - 2)

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
6 0

Answer:

x=1.13

Step-by-step explanation:

isolate the variable and the numbers and solve.

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PLEASE HELPPPP MEEEE NOWWWW!
Ket [755]

Answer:

2, 6, and 7

Step-by-step explanation:

3n is by itself because theres no other numbers that have the letter n.

6m and -11m are like terms bcs they both have the letter m (variable)

-3 and -18 are both like terms bcs they are both just numbers (or constants whatever)

so you would choose options 2, 6, and 7! hope this helps! :)

6 0
3 years ago
What is the number if 6/7 of 28 is equal to 30% of that number.
makkiz [27]

Answer:

80 is the actual number

Step-by-step explanation:

(28/7)(6)=24

24 x 100=2400

2400/30=80

80 x .3 = 24

5 0
3 years ago
The radius of the large sphere is double the radius of the
valentinak56 [21]

Answer:

8

Step-by-step explanation:

just do the comparation

Vb : Vs

b for big and s for small

4/3 π rb³ : 4/3 π rs³ (since there are 4/3 and π on both side, we can eliminate them so)

Vb : Vs = rb³ : rs³

Vb : Vs = (2rs)³ : rs³

Vb : Vs = 8rs³ : rs³ (delete the r³ on both side)

Vb : Vs = 8 : 1

so Vb is 8 times larger in volume than the small one

3 0
3 years ago
In the morning, a farm worker packed 3 pints of strawberries every 7 minutes. In the afternoon, she packed 2 pints of strawberri
Doss [256]
Morning:
3 pints every 7 minute = 3/7 pints/minute = 0.429 pints/minute

Afternoon:
2 pints every 5 minutes = 2/5 pints/minute = 0.4 pints/minute

Difference:
3/7 - 2/5 = 15/35 - 14/35 = 1/35 pints/minute

0.429 - 0.4 = 0.029 pints/minute
6 0
3 years ago
Read 2 more answers
The newest invention of the 6.431x staff is a three-sided die. On any roll of this die, the result is 1 with probability 1/2, 2
Gwar [14]

Answer:

<h2>The answer is 0.23(approx).</h2>

Step-by-step explanation:

The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.

We need to find the probability of getting exactly 3s as the result.

From the sequence of 6 independent rolls, 2 rolls can be chosen in ^6C_2 = \frac{6!}{2!\times4!} = \frac{30}{2} = 15 ways.

The probability of getting two 3 as outcome is \frac{1}{4} \times\frac{1}{4} = \frac{1}{16}.

In the rest of the 4 sequences, will not be any 3 as outcome.

Probability of not getting a outcome rather than 3 is 1 - \frac{1}{4} = \frac{3}{4}.

Hence, the required probability is 15\times\frac{1}{16}(\frac{3}{4})^4 = \frac{1215}{4096}≅0.2966 or, 0.23.

4 0
3 years ago
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