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Anvisha [2.4K]
3 years ago
14

Which of the expression can be used to find the area of a square with a side length of 1/3 m

Mathematics
1 answer:
jonny [76]3 years ago
7 0
1/3(2)=area
so the area is 2
_
3
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Answer: wheres the graph

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Simplify the expression 7y + 4x - 2x + 8
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thts gon be 7y+2x+8

Step-by-step explanation:

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Find a rational number that is between 5.2 and 5.5. explain why it is rational.
MaRussiya [10]

Answer:

5.3

Step-by-step explanation:

A rational number is a number that can be written as the quotient of two integers.

5.2 and 5.5 are both rational since they can be written as quotients of integers as shown below.

5.2 = 52/10

5.5 = 55/10

5.3 is a number between 5.2 and 5.5, and since 5.3 can be written as 53/10, it is rational.

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A study records the lengths of pregnancy (in days) of 500 women. The data is normally distributed with a mean of 266 days and a
VashaNatasha [74]

Answer:

<em>371 women had their pregnancy between 250 days and 282 days in length.</em>

di po ako sure sa answer ko, but it is based on what I remembered.

Step-by-step explanation:

z=<u>532-266</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u>1</u><u>6</u><u> </u><u> </u>

√500

= 371.74 or 371

4 0
3 years ago
Can anyone help me?
ArbitrLikvidat [17]

Answer:

The factored form of 4<em>m</em>³ – 28<em>m</em>² – 120<em>m</em> is 4<em>m</em>(<em>m</em> – 10)(<em>m</em> + 3). The zeroes of the function would be <em>m</em> = 0, <em>m</em> = –3, and <em>m</em> = 10.

Step-by-step explanation:

I'll give this a shot.

4<em>m</em>³ – 28<em>m</em>² – 120<em>m</em> = 0 — The original expression

4<em>m</em>³ – 28<em>m</em>² – 120<em>m</em> — Did that 0 have any purpose? I just deleted it.

4(<em>m</em>³ – 7<em>m</em>² – 30<em>m</em>) — There's a common factor in here, 4. Let's pull that aside.

4m(<em>m²</em> – 7<em>m</em> – 30) — Actually, there's <em>two</em> common factors. The second one is <em>m</em>! Let's pull <em>that</em> out too!

To factor an expression, you have to break apart the middle term, so to speak. That's only possible if you can find two numbers whose product equals that of the outside terms and whose sum equals the middle term. Here, I'm just dealing with numbers and putting that variable aside.

–30 = 10 × –3

–30 = –10 × 3

–30 = –2 × 15

–30 = 2 × –15 — To solve for any potential factors, let's find all the numbers integers that multiply to –30

Now let's see which one adds up to –7!

15 – 2 = 13 — it's not this one

2 – 15 = –13 — nor this one

10 – 3 = 7 — we're pretty close! Let's switch that negative

3 – 10 = –7 — here we go! Here's our numbers!

4<em>m</em>[(<em>m</em>² – 10<em>m</em>) + (3<em>m</em> – 30)] — now we break apart the middle term. This is <em>all</em> multiplied by 4<em>m</em>, so that still encases everything with brackets.

4<em>m</em>[<em>m</em>(<em>m</em> – 10) + 3(<em>m</em> – 10)] — Factoring the two expressions

4<em>m</em>(<em>m</em> + 3)(<em>m</em> – 10) — simplifying to find our answer! Ta-da!

8 0
3 years ago
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