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Sunny_sXe [5.5K]
2 years ago
12

Please please urgentttt !!!!! its geometry

Mathematics
1 answer:
jolli1 [7]2 years ago
8 0

Answer:

6,812,019 ft cubed

Step-by-step explanation:

1/3(b*h)

1/3(153^2*873)

1/3(23,409*873)

1/3(20,436,057) = 6,812,019

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3 years ago
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In a math class, 12 out of 15 girls are freshmen and 11 out of 15 boys are freshmen. What is the probability that in a randomly
SashulF [63]

Answer:

P(2FG|3FB) = \frac{605}{7917}

Step-by-step explanation:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter.To calculate combinations the below  formula is used:

nCr = \frac{n!}{r!(n-r)!}

where n represents the total number of items and r represent the number of items being chosen at a time. The '!' represents factorial function which is the product of all integers equal to and less than the given integer. This can be calculated manually using the formula or by using the nCr function on a scientific calculator.

Thus, the number of ways to select 2 freshmen girls (2FG) and 3 freshmen boys (3FB) can be determined. The number of ways to select 5 students (5S) can be determined in the same way.

2FG = 12C2 = \frac{12!}{2!(12-2)!} = \frac{12!}{2!(10)!} = 66

3FB = 11C3 = \frac{11!}{3!(11-3)!} = \frac{11!}{3!(8)!} = 165

5S = 30C5 = \frac{30!}{5!(30-5)!} = \frac{30!}{5!(25)!} = 142506

The probability of selecting 2 freshmen girls (2FG) and 3 freshmen boys (3FB) when selecting 5 students out of 30 is given as below:

P(2FG|3FB) = \frac{2FG*3FB}{5S} = \frac{66*165}{142506} = \frac{605}{7917}

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3 years ago
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Step-by-step explanation:

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