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Verdich [7]
2 years ago
14

This figure is the pre-image of a prism that has undergone a dilation with a scale factor of 3/4.

Mathematics
1 answer:
belka [17]2 years ago
5 0

The surface area of the image after the dilation is 219 3/8 m²

<h3>What is an area?</h3>

Area is the amount of space occupied by a two dimensional shape or object.

The surface area of the prism = 2(0.5 * 5 * 12) + (5 * 11) + (11 * 12) + (13 * 11) = 390 m²

The surface area of the image after the dilation = scale factor² *  390 m² = (3/4)² * 390 m² = 219 3/8 m²

The surface area of the image after the dilation is 219 3/8 m²

Find out more on area at: brainly.com/question/25292087

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Inessa05 [86]
I believe B But I am not sure I hope this helps . =D 
7 0
3 years ago
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Pls help I’m been stuck
ziro4ka [17]

Answer:

ANSWER: ADC=82

bda = 144

(7x+34)+(9x+46)=144

16x+80=144

16x=64

x=4

9(4)+46=82

adc=82

Step-by-step explanation:

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-5+d/3=5 solve the equation what does d equal
Aleks [24]
-5+d/3=5

d/3-5=5

d-3.5/3=5

d-15/3=5

d-15=15

(d-15)+15=15+15

d-15+15=30

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8 0
3 years ago
Write the equation in slope-intercept form. What are the slope and y-intercept?
Schach [20]
Slope intercept form is y=mx+b

Y= y intercept
M = slope
B = x intercept

-2x-11y= 5              get the y by itself
-11y = 2x + 5            divide by -11



y = -2/11x + 5/11

slope is -2/11
7 0
3 years ago
Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear
AlladinOne [14]

Answer:

x=\frac{83}{50}

Step-by-step explanation:

we know that

If the three points are collinear

then

m_A_B=m_A_C

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope AB

we have

A(1,\frac{2}{3}),B(x,-\frac{4}{5})

substitute in the formula

m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}

m_A_B=\frac{\frac{-12-10}{15}}{x-1}

m_A_B=-\frac{22}{15(x-1)}

step 2

Find the slope AC

we have

A(1,\frac{2}{3}),C(-\frac{1}{2},4)

substitute in the formula

m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}

m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}

m_A_C=-\frac{20}{9}

step 3

Equate the slopes

m_A_B=m_A_C

-\frac{22}{15(x-1)}=-\frac{20}{9}

solve for x

15(x-1)20=22(9)

300x-300=198

300x=198+300

300x=498

x=\frac{498}{300}

simplify

x=\frac{83}{50}

8 0
3 years ago
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