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mylen [45]
3 years ago
14

How many times does 64 go into 1760?

Mathematics
2 answers:
avanturin [10]3 years ago
8 0
64 goes into 1760, 27 times with .5 remaining
hope this helped!!
faust18 [17]3 years ago
6 0
Hi there!

To check this you can divide the two numbers. I'll show you:

64 goes into 1,760 about 27 times, with a .5 as a remainder. To check this when in doubt you can use a calculator and multiply 27.5 by 64 to get 1,760. :)

Hope this helps!
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PilotLPTM [1.2K]
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14 out of 22 students surveyed enjoyed playing baseball. If 308 students are surveyed, how many would you expect to say they enj
sergiy2304 [10]

Answer:

124

Step-by-step explanation:

14 -22=8

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Somehow 8 = 800%

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I got correct on this question but I wrote some of the numbers in a different order, is it okay if I wrote it in a different ord
Harman [31]

Answer:

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8 0
3 years ago
Help me please help me please
Olegator [25]
2=10
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7=35
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3 0
3 years ago
Read 2 more answers
please do the steps Solve for d: 1/6d-8=5/8 2. Solve for x: 3x-4+5x=10-2z 3. Solve for c: 7(c-3)=14 4. Solve for m: 11(m/22+3/44
xeze [42]

Answer:

d = 55.5  

x = 1

c = 11

m = \frac{1}{122}

k = \frac{a}{(c + 5)}

Step-by-step explanation:

Sorry, the formatting is slightly hard to understand, but I think this is what you meant.

Q1.

\frac{1}{6}d - 8 = \frac{5}{8} x 2

Step 1. Simplify.

\frac{5}{8} x 2 = \frac{5}{8} x \frac{2}{1} = \frac{10}{8}

Step 2. Cancel out the negative 8.

\frac{1}{6}d - 8 = \frac{10}{8}

+ 8 to both sides (do the opposite: \frac{1}{6}d is subtracting 8 right now, but to cancel that out, we will do the opposite of subtraction, i.e. addition)

\frac{1}{6}d = \frac{10}{8} + 8

Step 3. Simplify.

\frac{10}{8} + 8 = \frac{10}{8} + \frac{8}{1} = \frac{10}{8} + \frac{64}{8} = \frac{74}{8} = \frac{37}{4}

Step 4. Cancel out the \frac{1}{6}.

\frac{1}{6}d = \frac{37}{4}

÷ \frac{1}{6} from both sides (do the opposite: d is multiplied by \frac{1}{6} right now, but to cancel that out, we will do the opposite of multiplication, i.e. division)

÷ \frac{1}{6} = x 6

So....

x 6 to both sides

d = \frac{37}{4} x  6 = \frac{37}{4} x \frac{6}{1} = \frac{222}{4} = \frac{111}{2} = 55.5

Step 5. Write down your answer.

d = 55.5

Q2.

3x - 4 + 5x = 10 - 2x × 3

Step 1. Simplify

3x - 4 + 5x = 3x + 5x - 4 = 8x - 4

10 - 2x × 3 = 10 - (2x × 3) = 10 - 6x

Step 2. Cancel out the negative 6x

8x - 4 = 10 - 6x

+ 6x to both sides (do the opposite - you're probably tired of reading this now - right now it's 10 subtract 6x, but the opposite of subtraction is addition)

14x - 4 = 10

Step 3. Cancel out the negative 4

14x - 4 = 10

+ 4 to both sides (right now it's 14x subtract 4, but the opposite of subtraction is addition)

14x = 14

Step 4. Divide by 14

14x = 14

÷ 14 from both sides (out of the [14 × x] we only want the [x], so we cancel out the [× 14])

x = 1

Step 5. Write down your answer.

x = 1

Q3.

7(c - 3) = 14 × 4

Step 1. Expand the brackets

7(c - 3) = (7 x c) - (7 x 3) = 7c - 21

Step 2. Simplify

14 x 4 = 56

Step 3. Cancel out the negative 21

7c - 21 = 56

+ 21

7c = 56 + 21

7c = 77

Step 4. Cancel out the ×7

7c = 77

÷ 7

c = 77 ÷ 7

c = 11

Step 5. Write down your answer.

c = 11

Q4.

11(\frac{m}{22} + \frac{3}{44}) = 87m + m × 5

Step 1. Expand the brackets

11(\frac{m}{22} + \frac{3}{44}) = (11 x \frac{m}{22}) + (11 x \frac{3}{44}) = (\frac{11}{1} x \frac{m}{22}) + (\frac{11}{1} x \frac{3}{44}) = \frac{11m}{22} + \frac{33}{44} = \frac{m}{2} + \frac{3}{4}

Step 2. Simplify.

87m + m x 5 = 87m + 5m = 92m

Step 3. Cancel out the add \frac{3}{4}

\frac{m}{2} + \frac{3}{4} = 92m

- \frac{3}{4}

\frac{m}{2} = 92m - \frac{3}{4}

\frac{m}{2} = \frac{92m}{1} - \frac{3}{4}

\frac{m}{2} = \frac{368m}{4} - \frac{3}{4}

\frac{m}{2} = \frac{368m - 3}{4}

Step 4. Cancel out the ÷ 4

\frac{m}{2} = \frac{368m - 3}{4}

x 4

2m = 368m - 3

Step 5. Cancel out the 368m

2m = 368m - 3

- 368m

-366m = - 3

Step 6. Cancel out the × -366

-366m = -3

÷ -366

m = \frac{-3}{-366}

m = \frac{1}{122}

Step 7. Write down your answer.

m = \frac{1}{122}

Q5.

ck + 5k = a

Step 1. Factorise

ck + 5k = (c × k) + (5 × k) = (c + 5) x k = k(c + 5)

Step 2. Cancel out the × (c + 5)

k(c + 5) = a

÷ (c + 5)

k = a ÷ (c + 5)

k = \frac{a}{(c + 5)}

5 0
4 years ago
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