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puteri [66]
3 years ago
8

Do the ratios 2-4 and 14-7 form a proportion

Mathematics
2 answers:
irina1246 [14]3 years ago
7 0

Answer:

2=. 14

4 7

Cross multiply:

2 * 7 = 4 * 14

Simplifying

2 * 7 = 4 * 14

Multiply 2 * 7

14 = 4 * 14

Multiply 4 * 14

14 = 56

Solving

14 = 56

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution

Step-by-step explanation:

Nadya [2.5K]3 years ago
3 0

Answer:

No

Step-by-step explanation:

because 2 is divisible by 14 but 4 is not divisible by 17

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solmaris [256]

Answer:  15 units .

__________________________________________________

In this case, a square, the two sides of the square (forming a right triangle) are equal), and the "diagonal" forming is the hypotenuse of the right triangle.

In these cases, the measurements of the angles of the right triangle are "45, 45, 90" ; and the measurements of the sides are:  "a, a, a√2" ; in which "a√2" is the hypotenuse.

We are given:  "15√2" is the hypotenuse" ; and we are given that this is a right triangle of a square with a diagonal length (i.e. "hypotenuse" of "15√2" ; so the measure of the side of the "square" (and other two sides of the triangle formed) is:  15 units.   (i.e.,  15, 15, 15√2 ).

8 0
3 years ago
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Please help! Will give brainliest to correct answer
saveliy_v [14]

Answer:

Correct option is (C).

Step-by-step explanation:

Because in figure,

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5 0
3 years ago
Cassie’s score in a card game is 4 points away from zero. If Juanita’s score is the opposite of Cassie’s and is a negative value
zysi [14]
-4 is juanitas score.
5 0
3 years ago
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An urn contains 12 balls, of which 4 are white.
wel

Answer:

a) \frac{1}{3}

b) \frac{4}{12}\,,\,\frac{4}{11}\,,\,\frac{4}{10}\,,...

Step-by-step explanation:

Number of balls in the urn = 12

Number of white balls in the urn = 4

So, number of balls which are not white = 12 - 4 = 8

We know that probability = No. of outcomes/Total number of outcomes

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b)the balls that are withdrawn are not replaced.

Solution:

If A wins: P(A_1)=\frac{4}{12}=\frac{1}{3}

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If A and B lost and C wins: P\left ( C_1|A_1^{c}\,B_1^{c} \right )=\frac{4}{10}

and so on....

4 0
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enot [183]
D.
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3 years ago
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