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2 years ago

6

Hurry please

1 answer:

sweet-ann [11.9K]2 years ago

4 0

D . be after that if yyyy is still there at work

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Which graph represents the compound inequality?<br> n<-2 or n > 4

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Yes the answer is C. -2 to the left with open circle and 4 to the right with closed circle

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This service alerts you when there is a change in your credit report.

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What number would represent the outlier in the following set of data?

Mademuasel [1]

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3 years ago

Sally has a piece of cloth used 1/3 of a foot of the cloth to make a pillow cover in another 4/7 of a foot of the cloth to make

iren [92.7K]

Answer:

$\frac{23}{21} feets$

Step-by-step explanation:

Given.

Sally started with two feets of cloth.

Total cloth = $2 feets$

She used $\frac{1}{3}$ of a foot of the cloth to make a pillow cover.

And another $\frac{4}{7}$ of a foot of the cloth to make a table cloth.

She used total cloth to make a pillow cover and table cloth = $\frac{1}{3} +\frac{4}{7}$

$=\frac{7+12}{21} \\=\frac{19}{21}$

Total used cloth by Sally = $\frac{19}{21}$

The equation for remaining cloth

remaining cloth = total cloth - used cloth

remaining cloth $= 2 - \frac{19}{21}$

remaining cloth $= \frac{2\times 21-19}{21}$

remaining cloth $= \frac{42-19}{21}$

remaining cloth $= \frac{23}{21}$

Sally has remaining cloth = $\frac{23}{21}$ feets

8 0

3 years ago

8090 [49]

Step-by-step explanation:

$\large \rm \red{\widetilde{Taking\ RHS:-}}$

$\rm :\longmapsto \dfrac{1}{3 + \sqrt{7}} \ + \ \dfrac{1}{\sqrt{7} + \sqrt{5}} \ + \ \dfrac{1}{\sqrt{5} + \sqrt{3}} \ + \ \dfrac{1}{\sqrt{3} + 1}$

<u>Rationalizing, we get</u>

$\rm :\longmapsto \dfrac{1}{3+\sqrt7} \times \dfrac{3-\sqrt7}{3-\sqrt7} + \dfrac{1}{\sqrt7 + \sqrt5} \times \dfrac{\sqrt7 - \sqrt5}{\sqrt7 - \sqrt5}$

$\rm + \dfrac{1}{\sqrt5 + \sqrt3} \times \dfrac{\sqrt5 - \sqrt3}{\sqrt5-\sqrt3} + \dfrac{1}{\sqrt3 + 1} \times \dfrac{\sqrt3 - 1}{\sqrt3 -1}$

$\rm :\longmapsto \dfrac{3 - \sqrt7}{(3)^2 - (\sqrt7)^2}$

$+ \dfrac{\sqrt7 - \sqrt5}{(\sqrt7)^2 - (\sqrt5)^2}$

$+\dfrac{\sqrt5 - \sqrt3}{(\sqrt5)^2 - (\sqrt3)^2} +$

$\dfrac{\sqrt3-1}{(\sqrt3)^2 - 1^2}$

7 0

3 years ago

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