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Setler [38]
2 years ago
7

Which graph represents the compound inequality? n<-2 or n > 4

Mathematics
1 answer:
Marina86 [1]2 years ago
5 0
Yes the answer is C. -2 to the left with open circle and 4 to the right with closed circle
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17/9 15 divided 6 divided 30 divided and 3^3 from least to greatest
qaws [65]

I assume you mean: Order the following from least to greatest:

17/9, 15 divided by 6, 30, and 3^3

17/9 = 1 8/9

15/6 = 2 1/2

3^3 = 9

So it would be: 17/9, 15 divided by 6, 3^3, and 30

Make necessary adjustments if it was actually 6/30; the wording was confusing.


8 0
3 years ago
cole puts 68 books in a bookcase.he puts an equal number of books on each of 9 shelves and 5 books on the last shelf. how many b
fredd [130]
9x + 5 = 68
9x = 63
x = 7
Cole put seven books on each shelf.
3 0
3 years ago
Read 2 more answers
How 7,5,6 and 3 equal 75
____ [38]
Well first you do 7+5 to equal 12, and then you multiply 12 by 6 and get 72, then you add the 3 to get 75. 6(7+5)+3=75. Hope this helps!!
4 0
3 years ago
If a rectangular. Prism. Has 5cm. 10cm on one side and 4cm on the. Other. What is the volume of the rectangle?
emmasim [6.3K]

Answer: 200\ cm^3

Step-by-step explanation:

Given

The dimension of the rectangular prism is

l=5\ cm\\w=10\ cm\\h=4\ cm

The volume of the prism is given by V=l\times w\times h

\Rightarrow V=5\times 10\times 4\\\Rightarrow V=200\ cm^3

Therefore, the volume of the prism is 200\ cm^3.

7 0
2 years ago
Which of the following is equivalent to tan2θcos(2θ) for all values of θ for which tan2θcos(2θ) is defined?
Aloiza [94]

Answer:

2sin²θ - tan²θ

Step-by-step explanation:

Given

tan²θcos(2θ)

Required

Simplify

We start by simplifying cos(2θ)

cos(2θ) = cos(θ+θ)

From Cosine formula

cos(A+A) = cosAcosA - sinAsinA

cos(A+A) = cos²A - sin²A

By comparison

cos(2θ) = cos(θ+θ)

cos(2θ) = cos²θ - sin²θ ----- equation 1

Recall that cos²θ + sin²θ = 1

Make sin²θ the subject of formula

sin²θ = 1 - cos²θ

Substitute sin²θ = 1 - cos²θ in equation 1

cos(2θ) = cos²θ - (1 - cos²θ)

cos(2θ) = cos²θ - 1 +cos²θ

cos(2θ) = cos²θ + cos²θ - 1

cos(2θ) = 2cos²θ - 1

Substitute 2cos²θ - 1 for cos(2θ) in the given question

tan²θcos(2θ) becomes

tan²θ(2cos²θ - 1)

Open brackets

2cos²θtan²θ - tan²θ

------------------------

Simplify tan²θ

tan²θ = (tanθ)²

Recall that tanθ =  sinθ/cosθ

So, we have

tan²θ = (sinθ/cosθ)²

tan²θ = sin²θ/cos²θ

------------------------

Substitute sin²θ/cos²θ for tan²θ

2cos²θtan²θ - tan²θ becomes

2cos²θ(sin²θ/cos²θ) - tan²θ

Open bracket (cos²θ will cancel out cos²θ) to give

2(sin²θ) - tan²θ

2sin²θ - tan²θ

Hence, the simplification of tan²θcos(2θ) is 2sin²θ - tan²θ

Option E is correct

7 0
3 years ago
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