Ask question

Ask question

All categories

2 years ago

6

write two equations that when graphed look like this see image. please help its due soon and i will give ya 75 points for answ

ering, thanks, 5 stars, and brainlist. thank ya

1 answer:

myrzilka [38]2 years ago

6 0

Answer:

the graph is at 4 1/2 and 0 is that what you were looking for

Step-by-step explanation:

You might be interested in

What graph passes the vertical line test?

Marianna [84]

Answer:

The fourth image, or D.

Why?

If you had a ruler and placed it on the grid vertically and moved the ruler left to right, pictures A, B, and C, all have two points that lay on the same X point.

Picture D is the only one that has no points that lay on the same X point, thus making it the right answer.

Thank you for reading into this.

(Hope this helps you! ^^)

5 0

3 years ago

Read 2 more answers

What is the area of the circle shown below?

Andrew [12]

Answer:

201.06

Step-by-step explanation:

5 0

3 years ago

If the domain of f(n) = -4n - 3 is (-1, 1/4,4}, what is the range?

ahrayia [7]

Answer:

$Range= \{1,-4,-19\}$

Step-by-step explanation:

Given

$f(n) = -4n - 3$

$n = \{-1,1/4,4\}$ --- domain

Required

Determine the range

To do this, we simply substitute the values of n in the given expression

So, we have:

$n = -1$

$f(-1) = -4 * -1 - 3 =4 - 3 = 1$

$n = 1/4$

$f(-1) = -4 * 1/4 - 3 =-1 - 3 = -4$

$n=4$

$f(-1) = -4 * 4 - 3 =-16 - 3 = -19$

Hence, the range is:

$Range= \{1,-4,-19\}$

5 0

2 years ago

Find the lateral area for the pyramid with the equilateral base

likoan [24]

<h3>The lateral area for the pyramid with the equilateral base is 144 square units</h3>

<em><u>Solution:</u></em>

The given pyramid has 3 lateral triangular side

The figure is attached below

Base of triangle = 12 unit

<em><u>Find the perpendicular</u></em>

By Pythagoras theorem

$hypotenuse^2 = opposite^2 + adjacent^2$

Therefore,

$opposite^2 = 10^2 - 6^2\\\\opposite^2 = 100 - 36\\\\opposite^2 = 64\\\\opposite = 8$

<em><u>Find the lateral surface area of 1 triangle</u></em>

$\text{ Area of 1 lateral triangle } = \frac{1}{2} \times opposite \times base$

$\text{ Area of 1 lateral triangle } = \frac{1}{2} \times 8 \times 12\\\\\text{ Area of 1 lateral triangle } = 48$

<em><u>Thus, lateral surface area of 3 triangle is:</u></em>

3 x 48 = 144

Thus lateral area for the pyramid with the equilateral base is 144 square units

5 0

3 years ago

Select all that apply.

fomenos

First, third, fifth, and sixth answer

5 0

2 years ago

Read 2 more answers