Answer:
The data set with the greater range is the Girls
The greater median is the Girls at 110
Step-by-step explanation:
The range is the difference between the largest and smallest values.
As the largest value for the boys is 120 and the smallest is 60, the range would be 60
As the largest value for the girls is 150 and the smallest is 70, the range would be 80.
This means that the Girls have the greater range
The median is the number in the middle when the data is in ascending order.
As we have an even number, we will have to find the middle value between 5 and 6. To do this, we can add them together and divide them by 2.
The 5th boy in ascending order is 90 and the 6th boy is 90.
The 5th 5irl is 100 and the 6th girl is 120
This means that the median is greater for the Girls.
Answer:
the correct one is d
Step-by-step explanation:
so out 9
One way to go about this is to first list everything we know in the form of variables. This will make it easier to see how these numbers correlate instead of trying to remember formulas to plug these numbers into.
TimeA = 2.4h (time of Car A to travel)
TimeB = 4h (time of Car B to travel)
SpeedA = SpeedB + 22mph (Speed of Car A<span>)
</span>SpeedB = SpeedA - 22mph (Speed of Car B<span>)
</span>Distance = x (the distance traveled by each car)
We are looking for SpeedA. How can we find this? Well, we know that speed multiplied by time is equal to distance, so let's start there.
SpeedA * 2.4h = x
<span>(SpeedB + 22mph) * 2.4h = x
</span>(2.4h * SpeedB) + 52.8miles = x
We also know that:
SpeedB * 4h = x
Since both of these equations are equal to x, we can combine them:
SpeedB * 4h = x = <span>(2.4h * SpeedB) + 52.8miles
</span>SpeedB * 4h = <span>(2.4h * SpeedB) + 52.8miles
</span>1.6h * Speed B = 52.8miles
SpeedB = 52.8/1.6 mph = 33 mph
<span>SpeedA = SpeedB + 22mph = 33mph + 22mph = 55mph
</span>
Therefore, Car A was traveling at 55mph.
Answer:
-207xy
Step-by-step explanation:
-6x^3 - 9xy + 18x
-216x -9xy +18x
-225xy + 18x
-207xy
If I'm not mistaken.
