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bija089 [108]
3 years ago
5

M. A rectangular swimming pool is 5.4 m long and

Mathematics
1 answer:
Ber [7]3 years ago
8 0

Answer:

i need help please with my maths

Step-by-step explanation:

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F(x)=-4x^2+10x-8
vazorg [7]

Answer:

Step-by-step explanation:

a = - 4

b = 10

c = - 8

The discriminate is

D = b^2 - 4ac

D = 10^2 - 4*(-4)(-8)

D = 100 -  128

D = - 28 which is not a nice number

Because the Discriminate has a minus result, there are no real zeros.

6 0
3 years ago
Do ya'll have any suggestions about this?
Elanso [62]

Hello, I know your situation. Ask them for another chance. Ask them to forgive you and you will do your homework. Say "If this continues, then I accept full consiquinses". Make sure you ACTUALLY stick to what you say. Now, to the focusing part... Try to do ATLEAST 2 lessons for each class. (depends what school you are attending) If it seems that you are finishing too fast (less than 2 hrs), then do more homework until your homework hours fits you.

Goodluck!

God Bless you!!!

3 0
3 years ago
Read 2 more answers
Find the Ares of a semi circle whose radius is 2.4 cm​
GarryVolchara [31]

Answer:

Step-by-step explanation:

area of semi circle=πr^2/2

=3.14*(2.4)^2/2

=3.14*5.76/2

=18.0864/2

=9.0432 cm^2

3 0
3 years ago
Read 2 more answers
PLEASE HELP I WILL GIVE 200+ POINTS IF YOUR RIGHT ON ALL OF THEM
Yanka [14]

Answer:

A. = 8

2. = 12

3. = 10

4. = 14

5. = 9

Step-by-step explanation:

brainliest please?

7 0
3 years ago
The approximate distance between K and L is units. The approximate distance between L and J is units. If you join all three poin
ss7ja [257]

Answer:

The answer is below

Step-by-step explanation:

The distance between two points A(x₁, y₁) and B(x₂, y₂) on the coordinate plane is given by:

AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\

Point J is at (-3, 3), point K is at (4, 3) and point L is at (1, -1). Hence:

The distance between K and L = KL = \sqrt{(-1-3)^2+(1-4)^2} =5\ units

The distance between J and L = JL = \sqrt{(-1-3)^2+(1-(-3))^2} =4\sqrt{2} \ units

The distance between K and J = JK = \sqrt{(3-3)^2+(-3-4)^2} =7\ units

Therefore, the perimeter of triangle JKL is:

Perimeter = KL + JL + JK = 5 + 4√2 + 7 = 17.66 units

8 0
3 years ago
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