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3 years ago

M. A rectangular swimming pool is 5.4 m long and

Mathematics

1 answer:

Ber [7]3 years ago

8 0

Answer:

i need help please with my maths

Step-by-step explanation:

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Bob's Bakery makes 12 cakes and 36 muffins each hour.

N76 [4]

The answer is B hope it helped

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3 years ago

What is the length of side BD?

VashaNatasha [74]

Answer: 26.1

<u>Step-by-step explanation:</u>

$cos\theta=\dfrac{adjacent}{hypotenuse}\\\\\\cos(40^o)=\dfrac{20}{BD}\\\\\\BD=\dfrac{20}{cos(40^o)}\\\\\\BD=26.1$

4 0

3 years ago

Read 2 more answers

What is the biggest number possible in life?

Leona [35]

I don't think there is a large number because the numbers never end it expands. Interesting question.

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3 years ago

HELPELEPLEPELP this needed to be done last week LSMOAJOMOSN

denpristay [2]

Answer:

1/1

Step-by-step explanation:

try that if that doesnt work try 1 the question was confusing im sorry if its wrong...

3 0

3 years ago

you drop a ball from a height of 98 feet. at the same time, your friend throws a ball upward. the polynomials represent the heig

Ostrovityanka [42]

a) $h_0 -u_y t$

b) See interpretation below

Step-by-step explanation:

The motion of both balls is a free-fall motion: it means that the ball is acted upon the force of gravity only.

Therefore, this means that the motion of the ball is a uniformly accelerated motion, with constant acceleration equal to the acceleration of gravity:

$g=32 ft/s^2$

in the downward direction.

For the ball dropped from the initial height of $h_0 = 98 ft$ , the height at time t is given by

$h(t) = h_0 -\frac{1}{2}gt^2$ (1)

The ball which is thrown upward from the ground instead is fired with an initial vertical velocity $u_y$ , and its starting height is zero, so its position at time t is given by

$h'(t)=u_y t - \frac{1}{2}gt^2$ (2)

Therefore, the polynomial that represents the distance between the two balls is:

$h(t)-h'(t)=h_0 - \frac{1}{2}gt^2 - (u_y t - \frac{1}{2}gt^2) = h_0 -u_y t$

Now we interpret this polynomial, which is:

$\Delta h(t) = h_0 -u_y t$

which represents the distance between the two balls at time t.

The interpretation of the two terms is the following:

- The constant term, $h_0$ , is the initial distance between the two balls, at time t=0 (in fact, the first ball is still at the top of the building, while the second ball is on the ground). For this problem, $h_0 = 98 ft$

- The coefficient of the linear term, $u_y$ , is the initial velocity of the second ball; this terms tells us that the distance between the two balls decreases every second by $u_y$ feet.

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3 years ago