x2 - 12x = -6
Your next step would be to add 36 to both sides.
x2 - 12x + 36 = 30
In completing the square, we divide the term before x by 2, and then square it and add it to both sides.
12 / 2 = 6
6^2 = 36
That would be the next step.
Answer:
1. a
2. c
3. e
Step-by-step explanation:
1. a because she ran 5 miles on friday and ran x miles before friday. we know she had ran a total of 20 miles so we have x+5=20
2. there is a total of 20 clubs andre's school, 5 times more than is cousin's school. we have 20 =5x
3. 20 cats get 5 cups of food. each got an x amount. we get 5 =20x
Answer:
Camila
Step-by-step explanation:
you take 1/5 and make it 2/10. Then you see that there are 10 slices and since Beth and Camila ate in 10th's, Beth at 2 slices and Camila ate 3. So since Alice ate 2 slices its less than Camila. Therefore, Camila ate the most slices.
Answer:
Answer A.
Step-by-step explanation:
Recall that ![f(x) = \frac{x^2-4}{x-2}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7Bx%5E2-4%7D%7Bx-2%7D)
we will calculate the lateral limits of f when x approches x=2. Note that
![\lim_{x\to 2^{+}} \frac{x^2-4}{x-2} = \lim_{x\to 2^{+}} \frac{(x-2)(x+2)}{x-2} = 2+2 = 4](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%5Cto%202%5E%7B%2B%7D%7D%20%5Cfrac%7Bx%5E2-4%7D%7Bx-2%7D%20%3D%20%5Clim_%7Bx%5Cto%202%5E%7B%2B%7D%7D%20%5Cfrac%7B%28x-2%29%28x%2B2%29%7D%7Bx-2%7D%20%3D%202%2B2%20%3D%204)
![\lim_{x\to 2^{-}} \frac{x^2-4}{x-2} = \lim_{x\to 2^{-}} \frac{(x-2)(x+2)}{x-2} = 2+2 = 4](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%5Cto%202%5E%7B-%7D%7D%20%5Cfrac%7Bx%5E2-4%7D%7Bx-2%7D%20%3D%20%5Clim_%7Bx%5Cto%202%5E%7B-%7D%7D%20%5Cfrac%7B%28x-2%29%28x%2B2%29%7D%7Bx-2%7D%20%3D%202%2B2%20%3D%204)
We can clasify the discontinuity as follows:
- Removable discontinuity if both lateral limits are equal and finite.
- Jump discontinuity if both lateral limits are finite but different.
- Essential discontinuity if one of the limits is not finite and the other one is finite.
Based on this classification, since both lateral limits are equal, the discontinuity is a removable discontinuity