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Jet001 [13]
3 years ago
15

Perform the indicated operation. (14x^3y^2z)^4

Mathematics
2 answers:
Vlada [557]3 years ago
8 0

Answer:

​​  =38416x^12y^8z^4

nasty-shy [4]3 years ago
7 0

(14x³y²z)⁴ =

= 14⁴x¹²y⁸z⁴

= 38416x¹²y⁸z⁴

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What is the slope of (-3,-6) and (4,7)​
Gelneren [198K]

Answer:

13/7

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(7-(-6))/(4-(-3))

m=(7+6)/(4+3)

m=13/7

3 0
3 years ago
What is the value of e in e^x
Nookie1986 [14]

Answer

approximately 2.718

Step-by-step explanation

The exponential constant is an important mathematical constant and is given the symbol e. Its value is approximately 2.718. It has been found that this value occurs so frequently when mathematics is used to model physical and economic phenomena that it is convenient to write simply e.

7 0
3 years ago
one if the lights flickers every 7 seconds and the other light flickers very 8 seconds. how many seconds until both lights flick
bixtya [17]
It would be 56 seconds until both flicker at the same time

have a happy day :)
5 0
3 years ago
Read 2 more answers
Use Simpson's Rule with n = 10 to approximate the area of the surface obtained by rotating the curve about the x-axis. Compare y
DiKsa [7]

The area of the surface is given exactly by the integral,

\displaystyle\pi\int_0^5\sqrt{1+(y'(x))^2}\,\mathrm dx

We have

y(x)=\dfrac15x^5\implies y'(x)=x^4

so the area is

\displaystyle\pi\int_0^5\sqrt{1+x^8}\,\mathrm dx

We split up the domain of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [4, 9/2], [9/2, 5]

where the left and right endpoints for the i-th subinterval are, respectively,

\ell_i=\dfrac{5-0}{10}(i-1)=\dfrac{i-1}2

r_i=\dfrac{5-0}{10}i=\dfrac i2

with midpoint

m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4

with 1\le i\le10.

Over each subinterval, we interpolate f(x)=\sqrt{1+x^8} with the quadratic polynomial,

p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}

Then

\displaystyle\int_0^5f(x)\,\mathrm dx\approx\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx

It turns out that the latter integral reduces significantly to

\displaystyle\int_0^5f(x)\,\mathrm dx\approx\frac56\left(f(0)+4f\left(\frac{0+5}2\right)+f(5)\right)=\frac56\left(1+\sqrt{390,626}+\dfrac{\sqrt{390,881}}4\right)

which is about 651.918, so that the area is approximately 651.918\pi\approx\boxed{2048}.

Compare this to actual value of the integral, which is closer to 1967.

4 0
3 years ago
Witch of the following is NOT a characteristic of a plane?
Tanya [424]

Answer:

The answer would be "its width can be measured".

Step-by-step explanation:

8 0
3 years ago
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