P C
3 39
4 48
5 57
6 66
9(3)=27+12=39=c
9(4)=36+12=48=c
57=9p+12
-12 -12
45=9p
divide by 9 both sides 45/9=5=p
c=9(6)+12
c=54+12
c=66
Answer:
x < 40
Step-by-step explanation:
1 lbs for 5 pigs
The ratio is 1 lbs/ 5 pigs
Let x be the number of pigs
Take the ratio and multiply by the number of pigs, this has to be less than the amount of food in the stor
x * 1/5 < 8
Multiply each side by 5
x * 1/5 * 5 < 8*5
x < 40
Answer:
120 divided by 12 = 10
Step-by-step explanation:
The third one my dear sir!
a. The general form of equation of an uninhibited growth
model is:
A = a e^kt
where A is final amount, a is initial amount, k is
constant and t is time
From Monday to Wednesday, two days have passed so t = 2,
therefore calculating for constant k:
54 = 18 e^k(2)
e^2k = 3
2k = ln 3
k = 0.55
So the function becomes:
A(t) = a e^0.55t
b. Finding for t when A = 2a
2a = a e^0.55 t
0.55 t = ln 2
t = 1.26 days
