<span>If the company, hewerrtt, would like to make letter codes using all of the letters in the word hewerrtt, they would be able to make five codes. Altogether, there are eight letters in the word, but there are duplicates of the letter e, the letter r, and the letter t, so that takes out three possibilities. Three subtracted from eight is equal to five, therefore the company can make five codes using the company name.</span>
Answer:
all work is shown and pictured
Answer:
a) 1/64
b) 1/4096
Step-by-step explanation:
As you can tell from the example, the exponent of 1/2 is the number of heads in a row.
a) p(6 heads in a row) = (1/2)^6 = 1/(2^6) = 1/64
b) p(12 heads in a row) = (1/2)^12 = 1/(2^12) = 1/4096
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<em>Additional comment</em>
The probability of a head is 1/2 because we generally are concerned with a "fair coin." That is defined as a coin in which each of the 2 possible outcomes has the same probability, 1/2. Similarly, a "fair number cube" has 6 faces, and the probability of each is defined to be the same as any other, 1/6. Loaded dice and unfair coins do sometimes show up in probability problems.
Answer:
4/7
Step-by-step explanation:
2/7 ÷1/2=2/7 × 2 = 4/7
Hope this helps :D
Answer: Verizon is less expensive than the S&P 500 on both a P/E and dividend yield basis.
Step-by-step explanation:
When a <em>Price to Earnings ratio is relatively high</em> this means that the <em>Price of the security is high </em>because investors believe the company has good prospects.
When a Dividend Yield is relatively low, this means that the dividends being declared are quite lower than the price because Dividend yield is dividends as a percentage of security price. <em>Lower Dividend Yields therefore mean high security prices</em>.
Looking at the Verizon Chart and the S&P 500 you see that Verizon P/E ratio is 11.71 while S&P is 19.01.
This means that the price of Verizon's is less than S&P 500.
Also notice that Verizon's Dividend yield is 4.09% while S&P 500's is 1.91% again signifying that Verizon is cheaper.
I have attached the full question.