Answer:
Part 1) 
Part 2) 
Part 3) m∠K=61°
Part 4) m∠L=119°
Part 5) m∠M=61°
Step-by-step explanation:
we know that
In a parallelogram opposite angles and opposite sides are congruent and consecutive angles are supplementary
Part 1) Find the side MN
we know that
MN≅KL ----> by opposite sides
we have

therefore

Part 2) Find the side KN
we know that
KN≅LM ----> by opposite sides
we have

therefore

Part 3) Find the measure of angle K
we know that
m∠K+m∠N=180° ----> by consecutive interior angles
we have
m∠N=119°
substitute
m∠K+119°=180°
m∠K=180°-119°
m∠K=61°
Part 4) Find the measure of angle L
we know that
m∠L≅m∠N ----> by opposite angles
we have
m∠N=119°
therefore
m∠L=119°
Part 5) Find the measure of angle M
we know that
m∠M≅m∠K ----> by opposite angles
we have
m∠K=61°
therefore
m∠M=61°
Yes............................
<span>He then drank 35 percent of the water in the container
so 65% left in in the container
0.65 x 500 = 325 </span><span>milliliter
answer
</span>325 milliliter of water left in the container
Answer:
Therefore,

Step-by-step explanation:
Given:
![A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%266%269%5C%5C2%264%268%5C%5C%5Cend%7Barray%7D%5Cright%5D)
To Find:
a₂₁ = ?
Solution:
Let,
![A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da_%7B11%7D%26a_%7B12%7D%26a_%7B13%7D%5C%5Ca_%7B21%7D%26a_%7B22%7D%26a_%7B23%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
We require ' a₂₁ ' i.e Second Row First Column Element
So on Comparing we get
∴ 
Therefore,

Answer:
5 different numbers, 2 even
Step-by-step explanation:
Since we have 5 digits and they are non repeating we can use the permutation formula:

It gives us the amount of ways to arrange k objects out of n objects without repetition, but order does matter.
In our case the amount of 4 digit numbers that can be formed using the digits from 1 to 5 is: 
And out of those 5, only 2 are even