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ohaa [14]
3 years ago
8

The triangle inequality

Mathematics
1 answer:
klemol [59]3 years ago
3 0
The answer is the first choice: 7, 15, 20.
When you want to know what three numbers can make up a triangle. All you have to do is take the first two numbers and add them up. If the sum is larger than the third number, it can form a triangle. If the sum of the first two numbers are smaller than the third number, it cannot form a triangle.
Hope this helped
You might be interested in
If each quadrilateral below is a parallelogram,find the missing measures.
zhenek [66]

Answer:

Part 1) MN=31\ units

Part 2) KN=45\ units

Part 3) m∠K=61°

Part 4) m∠L=119°

Part 5) m∠M=61°

Step-by-step explanation:

we know that

In a parallelogram opposite angles and opposite sides are congruent and consecutive angles are supplementary

Part 1) Find the side MN

we know that

MN≅KL ----> by opposite sides

we have

KL=31\ units

therefore

MN=31\ units

Part 2) Find the side KN

we know that

KN≅LM ----> by opposite sides

we have

LM=45\ units

therefore

KN=45\ units

Part 3) Find the measure of angle K

we know that

m∠K+m∠N=180° ----> by consecutive interior angles

we have

m∠N=119°

substitute

m∠K+119°=180°

m∠K=180°-119°

m∠K=61°

Part 4) Find the measure of angle L

we know that

m∠L≅m∠N ----> by opposite angles

we have

m∠N=119°

therefore

m∠L=119°

Part 5) Find the measure of angle M

we know that

m∠M≅m∠K ----> by opposite angles

we have

m∠K=61°

therefore

m∠M=61°

7 0
3 years ago
Did I do number 3 Part A right? If not may someone please explain? Thanks
kolezko [41]
Yes............................
6 0
3 years ago
Reyansh filled a 500-milliliter container with clean water. He then drank 35 percent of the water in the container. How many mil
galben [10]
<span>He then drank 35 percent of the water in the container
so 65% left in in the container

0.65 x 500 = 325 </span><span>milliliter 

answer
</span>325 milliliter of water left in the container
3 0
3 years ago
Read 2 more answers
SOMEONE PLEASE HELP ME ASAP PLEASE!!!!​
ehidna [41]

Answer:

Therefore,

a_{21}=2

Step-by-step explanation:

Given:

A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right]

To Find:

a₂₁ = ?

Solution:

Let,

A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\\end{array}\right]

We require  ' a₂₁ ' i.e Second Row First Column Element

So on Comparing we get

∴ a_{21}=2

Therefore,

a_{21}=2

5 0
3 years ago
Find the number of 4 digit numbers that can be formed using the digits 1,2,3,4,5 if no digits is no repeated
loris [4]

Answer:

5 different numbers, 2 even

Step-by-step explanation:

Since we have 5 digits and they are non repeating we can use the permutation formula:

P(n, k) = \frac{n!}{k!}, $where $ k \leq n ; k, n \in \mathbb{N}

It gives us the amount of ways to arrange k objects out of n objects without repetition, but order does matter.

In our case the amount of 4 digit numbers that can be formed using the digits from 1 to 5 is: P(5, 4) = \frac{5!}{4!} = 5.

And out of those 5, only 2 are even

4 0
3 years ago
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