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sattari [20]
2 years ago
9

Which equation represents the polar form of x – y = 0?

Mathematics
1 answer:
adoni [48]2 years ago
3 0

Answer:

x means 2 and y means -2

Step-by-step explanation:

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There are 21 students in a class. The median age of the students is 23. The oldest student is 29.
Varvara68 [4.7K]

Answer:

1) At least one (the 11th) student is 23 (years old), <u>Must be true</u>

2) Some students are younger than 15 <u>Could be true</u>

Step-by-step explanation:

1) The given parameters are;

The number of student in the class = 21

The median age of the student = 23

The age of the oldest student = 29

Therefore, given that the median age = The age of the (n + 1)/2 th student

Where;

n = The number of student in the class = 21

∴ The median age = The age of the (21 + 1)/2 th = 11 th student, when the age of the students are arranged in increasing order, therefore, we have;

At least one (the 11th) student is 23 (years old), <u>Must be true</u>

2) Given that there are 10 students with ages equal to or lower than the  median age, and the difference between the median age and the age of the oldest student = 29 - 23 = 6 years, we have;

Some students are younger than 15 <u>Could be true</u>

5 0
3 years ago
I need help with this please
kodGreya [7K]
1/5(2x - 10) + 4x = -3(1/5x + 4)
0.4x - 2 + 4x = -0.6x - 12
4.4x - 2 = -0.6x - 12
5x - 2 = -12
5x = -10
x = -2
6 0
3 years ago
Read 2 more answers
Find the perimeter or circumference and area
Romashka [77]

Answer:

Step-by-step explanation:

The diameter is just the radius times two, so divide the diameter by two and you will have the radius of the circle.

4 0
3 years ago
Give an example of a number between 20 and 50 which is a multiple of 3 and also a factor of 84.​
Kazeer [188]

Answer:

69

Step-by-step explanation:

by eliminating 20 from 84 we get 64 then add the 3 to get 67 and then we know that we always add 2 to our answers and therefore get 69

6 0
3 years ago
HELP HOW DO I SOLVE THE FOLLOWING? PLEASE HELP
levacccp [35]
f(x) = \sqrt[3]{2x - 1} \\f(14) = \sqrt[3]{2(14) - 1} \\f(14) = \sqrt[3]{28 - 1} \\f(14) = \sqrt[3]{27} \\f(14) = 3

f(x) = \sqrt[3]{2x - 1} \\f(-62) = \sqrt[3]{2(-62) - 1} \\f(-62) = \sqrt[3]{-124 - 1} \\f(-62) = \sqrt[3]{-125} \\f(-62) = -5

f(x) = \sqrt[3]{2x - 1} \\f(20) = \sqrt[3]{2(20) - 1} \\f(20) = \sqrt[3]{40 - 1} \\f(20) = \sqrt[3]{39}
4 0
3 years ago
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