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wlad13 [49]
2 years ago
14

Correct answer will get brainliest :)

Mathematics
1 answer:
klasskru [66]2 years ago
5 0
<h2><em><u>Answer:</u></em></h2>

<h2><em><u>omg I brilliant but I won't say the answer lol I don't know why</u></em></h2>
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Which expression is equivalent to 27 ( − 2 3 x + 1 3 ) − 5 x ?
klemol [59]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Neep help pls, what is the answer????
saveliy_v [14]

Answer:

No, According to triangle Inequality theorem.

Step-by-step explanation:

Given:

Length given are 4 in., 5 in., 1 in.

We need to check whether with these lengths we can create triangular components.

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side.

These must be valid for all three sides.

Hence we will check for all three side,

4 in + 5 in > 1 in. (It is a Valid Condition)

1 in + 5 in > 4 in. (It is a Valid Condition)

4 in + 1 in > 5 in. (It is not a Valid Condition)

Since 2 condition are valid and 1 condition is not we can say;

A triangular component cannot be created with length 4 in, 5 in, and 1 in by using triangle inequality theorem (since all three conditions must be valid).

6 0
3 years ago
Is 8.012 greater than 8.03
morpeh [17]
Answer: No, 8.03 is greater than 8.012
8 0
2 years ago
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3 pounds of bannas cost $1.5 What is the costant of this proportionly that relates the cost in dollars y,to the number of pounds
Sergeu [11.5K]

Answer:

.50 cents per pound

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Plz help me!!!!
sveta [45]
A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.

b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
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3 years ago
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