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Marysya12 [62]
2 years ago
8

An equation is shown below:

Mathematics
2 answers:
lisov135 [29]2 years ago
5 0

Answer: x = 1

Step-by-step explanation:

5 ( 2x - 8 ) + 15 = -15 (write the equation)

5 ( 2x - 8 ) = -30 (subtract by 15 on both sides)

2x - 8 = -6 (divide by 5 on both sides)

2x = 2 (add 8 to both sides)

x = 1 (divide by 2 on both sides)

MrRa [10]2 years ago
5 0

Answer:

x = 1

Step-by-step explanation:

<u>Skills needed: One-Variable Equations, Solving Equations</u>

1) The first thing is to use P.E.M.D.A.S

There are no Parentheses, or Exponents, so we go to multiplication

The quantity we multiply is: 5(2x-8)

Using distributive property (which is a(b+c) = ab+ac), you get:

5(2x-8) = 5(2x) - 5(8) = 10x - 40

2) Now, we substitute back in and combine like terms:

10x-40+15=-15

Combine the -40 and 15 (-40+15=-25)

Then, you will get: (10x-25=-15)

3) Add 25 to both sides, to isolate the variable:

10x = -15+25, and then -15+25 is 10, so

10x = 10

4) Divide by 10 on both sides, and get x = 1

Hope this helps and have a nice day!! :) :]

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3 0
3 years ago
Mohamed and Li Jing were asked to find an explicit formula for the sequence -5, -25, -125, -625,....
Nuetrik [128]

Answer:

Li Jing's formula i.e.  \boxed{g_n=-5\cdot \:5^{n-1}}  is right.

Step-by-step explanation:

Considering the sequence

-5,\:-25,\:-125,\:-625,...

A geometric sequence has a constant ratio r and is defined by

g_n=g_0\cdot r^{n-1}

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{g_{n+1}}{g_n}

\frac{-25}{-5}=5,\:\quad \frac{-125}{-25}=5,\:\quad \frac{-625}{-125}=5

\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

r=5

So, the sequence is geometric.

as

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

g_1=-5

r=5

so

g_n=g_1\cdot r^{n-1}

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

g_n=-5\cdot \:5^{n-1}

Therefore, Li Jing's formula i.e.  \boxed{g_n=-5\cdot \:5^{n-1}}  is right.

8 0
3 years ago
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