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3 years ago

I GIVE BRAiNIEsT THInG S HeLP iM TImED

Mathematics

2 answers:

Levart [38]3 years ago

8 0

The answer is C. I am positive is it C.

nataly862011 [7]3 years ago

6 0

C is the answer I think sorry if I’m incorrect

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How do u simplify 2(x+3) using distributive property

Serjik [45]

Answer:

2x + 6

Step-by-step explanation:

You multiply 2 by the numbers in parentheses. 2 times x is 2x, and 2 times 3 is 6.

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3 years ago

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2 7/8 plus 3 2/8 plus 1 1/8

Olin [163]

Answer:

7.25

Step-by-step explanation:

2 7/8 + 3 2/8 * 1 1/8 = 7.25

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4 years ago

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Factor x3y6 + 27z42. (xy3 + 3z39)(x2y9 – 3xy3z39 + 9z1,521) (xy3 + 3z39)(x2y6 – 3xy3z39 + 9z78) (x3y6 + 27z42)(x6y12 – 27x3y6z42

Licemer1 [7]

Answer:

$x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})$

Step-by-step explanation:

Given

$x^3y^6 + 27z^{42$

Required

Factor

Express both terms as a cube

$x^3y^6 + 27z^{42} = (xy^2)^3 + (3z^{14})^3$

Let

$a =(xy^2)$

$b = (3z^{14})$

So:

$x^3y^6 + 27z^{42} = a^3 + b^3$

Using sum of cubes:

$a^3 + b^3 = (a + b)(a^2 - ab + b^2)$

So:

$x^3y^6 + 27z^{42} = (a + b)(a^2 - ab + b^2)$

Substitute in, values of a and b

$x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})((xy^2)^2 - (xy^2)*(3z^{14}) + (3z^{14})^2)$

$x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})$

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3 years ago

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Solve the following systems of linear equations. [3x+7y= -4 and 2x+5y= -3]

Sophie [7]

Eliminate
multiply first equatin by -2
mulitply second by 3 and add them

-6x-14y=8
6x+15y=-6
add them
y=2
sub

3x+7(2)=-4
3x+14=-4
minus 14
3x=-18
divide 3
x=-6
(-6,2)

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3 years ago