In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.
To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9
To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum). The probability is 11/36
Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.
P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
62 is 50% of 124 (62*2=124)
Answer:
Step-by-step explanation:
Let L be the given line, then, with a slope of -8
L : y = -8x + b
where b is to be determined from the included point A(-10,0).
Substitute point A in L to get
0 = -8 (-10) + b
solve to get
b = -80
therefore
L : y = -8x -80
Now substitute B(-9,z) in L
z = -8(-9) - 80 = -8
Answer:
Fraction: 23/100
Decimal: 0.23
Percent: 23%
Step-by-step explanation:
Hope this helps!
Answer:
made 25%
Step-by-step explanation:
