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kozerog [31]
2 years ago
7

Miguel invested $400 in a bank account that pays interest. the account’s value over time, in x years, is given in the table. a 2

-column table with 6 rows. the first column is labeled time (years) with entries 0, 1, 2, 3, 4, 5. the second column is labeled account value (dollar sign) with entries 400, 436, 468, 502, 550, 589. which exponential function models the data? round the numerical values to the nearest hundredth. f(x) = 1.41(30.69)x f(x) = 37.74(396.48)x f(x) = 390.60(1.41)x f(x) = 401.19(1.08)x
Mathematics
1 answer:
fenix001 [56]2 years ago
4 0

The exponential function models the data for the amount earned by Miguel when he invests his money is f(x) = $400 x (1.08)^y

<h3>What is the exponential function?</h3>

Exponential functions are in the form: ab^{x}

Where:

  • a = initial value
  • b = rate of increase
  • x = number of years

FV = $400 x (1.08)^y

To learn more about exponential functions, please check: brainly.com/question/26331578

#SPJ4

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Step-by-step explanation:

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15 . Undefined

16. undefined

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Darpana solved the equation s = StartFraction a + b + c Over 3 EndFraction for a. Her steps are shown below: 1. Multiply by 3: s
Harman [31]

Answer:

Option (c) is correct.

Step-by-step explanation:

Given equation is :

s=\dfrac{a+b+c}{3}

The equation can be solved for a as follows :

Step 1.

Cross multiply the given equation

3s=a+b+c

Step 2.

Now subtract b on both sides

3s-b = a+b+c-b

3s-b = a+c

Step 3.

Subtract c on both sides

3s-b-c=a+c-c

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The statement that is true for Darpana is " In step 3, she needed to subtract c rather than divide".

5 0
3 years ago
Read 2 more answers
A pumpkin is thrown horizontally off of a building at a speed of 2.5\,\dfrac{\text m}{\text s}2.5 s m ​ 2, point, 5, start fract
4vir4ik [10]

Answer:−47.0

​

​

Step-by-step explanation:Step 1. List horizontal (xxx) and vertical (yyy) variables

xxx-direction yyy-direction

t=\text?t=?t, equals, start text, question mark, end text t=\text?t=?t, equals, start text, question mark, end text

a_x=0a

x

​

=0a, start subscript, x, end subscript, equals, 0 a_y=-9.8\,\dfrac{\text m}{\text s^2}a

y

​

=−9.8

s

2

m

​

a, start subscript, y, end subscript, equals, minus, 9, point, 8, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction

\Delta x=12\,\text mΔx=12mdelta, x, equals, 12, start text, m, end text \Delta y=\text ?Δy=?delta, y, equals, start text, question mark, end text

v_x=v_{0x}v

x

​

=v

0x

​

v, start subscript, x, end subscript, equals, v, start subscript, 0, x, end subscript v_y=\text ?v

y

​

=?v, start subscript, y, end subscript, equals, start text, question mark, end text

v_{0x}=2.5\,\dfrac{\text m}{\text s}v

0x

​

=2.5

s

m

​

v, start subscript, 0, x, end subscript, equals, 2, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction v_{0y}=0v

0y

​

=0v, start subscript, 0, y, end subscript, equals, 0

Note that there is no horizontal acceleration, and the time is the same for the xxx- and yyy-directions.

Also, the pumpkin has no initial vertical velocity.

Our yyy-direction variable list has too many unknowns to solve for v_yv

y

​

v, start subscript, y, end subscript directly. Since both the yyy and xxx directions have the same time ttt and horizontal acceleration is zero, we can solve for ttt from the xxx-direction motion by using equation:

\Delta x=v_xtΔx=v

x

​

tdelta, x, equals, v, start subscript, x, end subscript, t

Once we know ttt, we can solve for v_yv

y

​

v, start subscript, y, end subscript using the kinematic equation that does not include the unknown variable \Delta yΔydelta, y:

v_y=v_{0y}+a_ytv

y

​

=v

0y

​

+a

y

​

tv, start subscript, y, end subscript, equals, v, start subscript, 0, y, end subscript, plus, a, start subscript, y, end subscript, t

Hint #22 / 4

Step 2. Find ttt from horizontal variables

\begin{aligned}\Delta x&=v_{0x}t \\\\ t&=\dfrac{\Delta x}{v_{0x}} \\\\ &=\dfrac{12\,\text m}{2.5\,\dfrac{\text m}{\text s}} \\\\ &=4.8\,\text s \end{aligned}

Δx

t

​

 

=v

0x

​

t

=

v

0x

​

Δx

​

=

2.5

s

m

​

12m

​

=4.8s

​

Hint #33 / 4

Step 3. Find v_yv

y

​

v, start subscript, y, end subscript using ttt

Using ttt to solve for v_yv

y

​

v, start subscript, y, end subscript gives:

\begin{aligned}v_y&=v_{0y}+a_yt \\\\ &=\cancel{0\,\dfrac{\text m}{\text s}}+\left(-9.8\,\dfrac{\text m}{\text s}\right)(4.8\,\text s) \\\\ &=-47.0\,\dfrac{\text m}{\text s} \end{aligned}

v

y

​

​

 

=v

0y

​

+a

y

​

t

=

0

s

m

​

​

+(−9.8

s

m​

)(4.8s)

=−47.0

s

m

5 0
3 years ago
Read 2 more answers
If the quotient of a number and 8 is added to 1/2
Effectus [21]
(x/8)+(1/2)=7/8
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