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natita [175]
3 years ago
8

Factorise : 64a cube minus 27b cube minus 144a square b plus 108ab square ​ .

Mathematics
1 answer:
Ad libitum [116K]3 years ago
8 0

Answer:

<h2>The answer is 4a(16a^2+27b^2)-3b(9b^2+48b)</h2>

Step-by-step explanation:

step one:

let us re-write the expression in mathematical terms for clarity

we have the expression stated  below

64a^3-27b^3-144b^2+108ab^2    

step two:

We are going to collect like terms before factorization we have

    64a^3+108ab^2-27b^3-144b^2

We can now factorize the expression we have  

4a(16a^2+27b^2)-3b(9b^2+48b)

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Help? I can't seem to understand arithmegic sequence.
katrin2010 [14]

A sequence \{a_n\} is arithmetic if the difference between consecutive terms is some fixed number, regardless of which pair of consecutive terms you pick out of the sequence.

For example, the following sequences are arithmetic:

1, 2, 3, 4, 5, 6, ... (difference = 1)

-25, -20, -15, -10, -5, ... (difference = 5)

2. Carla's sequence is not arithmetic, because the differences between consecutive terms are all different:

13 - 11 = 2

17 - 13 = 4

25 - 17 = 8

She can adjust the sequence by changing the last two numbers to 15 and 17, since this makes the difference fixed:

13 - 11 = 2

15 - 13 = 2

17 - 15 = 2

and so on.

3. The sequence

45, 48, 51, 54, ...

is arithmetic with difference 3 between terms. Recursively, we can write the nth term, a_n, in terms of the previous, (n-1)th term, a_{n-1}:

a_n=a_{n-1}+3

By this definition, we can just as easily write the (n-1)th term in terms of the (n-2)th term:

a_{n-1}=a_{n-2}+3

Then, substituting this into the previous equation, we have

a_n=(a_{n-2}+3)+3=a_{n-2}+2\cdot3

We can continue this process to write a_n in terms of a_1:

a_{n-2}=a_{n-3}+3\implies a_n=a_{n-3}+3\cdot3

a_{n-3}=a_{n-4}+3\implies a_n=a_{n-4}+4\cdot3

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a_n=a_1+(n-1)\cdot3

The first term in this sequence is a_1=45, so we have

a. a_n=45+3(n-1)=42+3n

where n=1,2,3,\ldots.

b. You can fill in the blanks by just adding 3 to the previous term:

45, 48, 51, 54, <u>57</u>, 60, <u>63</u>, 66, 69, ...

Then, using the formula found in (a), the 15th term of the sequence is

a_{15}=42+3\cdot15=87

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3 years ago
What do we call the polynomial obtained when a given polynomial is divided by one of its factors?
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Answer:

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Step-by-step explanation:

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