We have that
<span>(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)
</span>- 1/(2-c)=-1/-(c-2)=1/(c-2)
(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2)
(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)
(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14
the solution is c=14
the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or
<span>all real numbers except c=-2 and c=2</span>
Answer:
0
Step-by-step explanation:
Anything times 0 is 0.
Answer:
- 33°
- 90° -J°
Step-by-step explanation:
<h3>1)</h3>
If x represents the measure of the angle, its complement is 90-x. The problem statement tells us ...
x +24 = 90 -x
2x = 66 . . . . . add x-24
x = 33 . . . . . . divide by 2
The measure of the angle is 33°.
__
<h3>2)</h3>
Using J for x in the given complement relation:
The measure of the complement of J° is (90 -J)°.
Answer:
1/4 Teaspoons: 7
1/3 Cup: 20
Step-by-step explanation:
1/3 Cup:
Butter (2), Sugar (4), Coca (3), Flour(11)
1/4 Teaspoon:
Salt (3), Baking Soda (4)
Answer:
Step-by-step explanation:
The vertex will occur when t=-b/(2a) for the quadratic ax^2+bx+c
In this case
t=-200/(2(-16))
t=-200/-32
t=6.25
g(6.25)=-16(6.25^2)+200(6.25)
g(6.25)=625ft
So the maximum height of the rocket is 625 feet and it reaches this height at 6.25 seconds.
