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Kipish [7]
2 years ago
11

Wesley has started to collect sports cards. The graph

Mathematics
2 answers:
solmaris [256]2 years ago
4 0

Answer:

B

Step-by-step explanation:

It goes up by one, to the right by 2. Or flip that, Im dyslexic

natulia [17]2 years ago
3 0

Answer:

B!!

Step-by-step explanation:

Hope nthis helps!!!!!

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Simply the radical expression 189
Wittaler [7]

Answer

13

Step-by-step explanation:

3 0
3 years ago
Fred the ant is on the real number line, and Fred is trying to get to the point $0.$
Pavlova-9 [17]

Complete question is;

Fred the ant is on the real number line, and Fred is trying to get to the point 0

If Fred is at 1 then on the next step, Fred moves to either 0 or 2 with equal probability. If Fred is at 2 then on the next step, Fred always moves to 1

Let e1 be expected number of steps Fred takes to get to 0 given that Fred starts at the point 1. Similarly, let e2 be expected number of steps Fred takes to get to 0 given that Fred starts at the point 2

Determine the ordered pair (e1, e2)

Answer:

(e_1,e_2) = (2,3)

Step-by-step explanation:

We can track the probabilities using the scenario that Ant gets to 0 after 1 steps, 2 steps, 3 steps, 4 steps, 5 steps and so on.

This gives us e_1 = 1(1/2^(1)) + 2(1/2²) + 3(1/2³) + 4(1/2⁴) + ...

By arithmetico-geometric series, which is given by;

S_(∞) = [a/(1 - r)] + dr/(1 - r)²

From the online calculator, i got;

e_1 = 2

Similarly, e_2 = 2(1/2^(1)) + 3(1/2²) + 4(1/2³) + 5(1/2⁴) + ...

By arithmetico-geometric series, e_2 = 3,

Thus, (e_1,e_2) = (2,3).

6 0
3 years ago
To determine the number of squirrels in a conservation area a researcher cashers tags and releases 114 squirrels you later catch
Ede4ka [16]

Answer:

336 squirrels

Step-by-step explanation:

-This is a Mark-Recapture method.

-The population is estimated using the formula:

N=\frac{MC}{R}

where:

  • N-is the estimated population size.
  • M-is the number of individuals tagged
  • C- is the total number captured the second time(both tagged and untagged)
  • R-is the total number of tagged individuals recaptured.

#We substitute our values as follows to estimate N:

N=\frac{MC}{R}\\\\=\frac{114\times 97}{33}\\\\=335.0909\approx336

Hence, there are approximately 336 squirrels in the conservation area.

*population is always rounded up to the next whole number.

5 0
3 years ago
Can someone help me with this??<br><br> thanks
viva [34]
Number of tickets: T.
Number of customers: c 
Initially the number of tickets is T0=150, when the group hasn't sold any tickets (c=0). Then the graph must begin with c=0 and T=150. Point=(0,150). Possible options: Graph above to the right and graph below to the left.
They sell the tickets in pack of three tickets per customer c, then each time they sell a pack of three tickets to a customer, the number of tickets is reduced by 3 (-3c). Then the number of tickets, T, the group has left after selling tickets to c customers is:
T=150-3c→T=-3c+150

For T=0→-3c+150=0→150=3c→150/3=c→c=50. The graph must finish with c=50, T=0. Final point=(c,T)=(50,0)

Answer:
The correct graph is above to the right, beginning on vertical axis with T=150 and finishing on horizontal axis with c=50.
The correct equation is T=-3c+150

7 0
3 years ago
Read 2 more answers
4/5 divided by 1/3 plus 1/5 minus 3/5
r-ruslan [8.4K]

Answer:

  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

Step-by-step explanation:

Considering the expression

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

Solution Steps:

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

as

\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}

so

=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}    

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}

join  \frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}

so

=\frac{4}{5\left(-\frac{1}{15}\right)}

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=\frac{4}{-5\cdot \frac{1}{15}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}

=-\frac{4}{5\cdot \frac{1}{15}}

\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}

so

=-\frac{4}{\frac{1}{3}}

\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}

so

=-\frac{12}{1}

\mathrm{Apply\:rule}\:\frac{a}{1}=a

=-12

Therefore

                  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

4 0
3 years ago
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