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3 years ago

Please can u help me

Mathematics

2 answers:

Amanda [17]3 years ago

8 0

The answer is 1.2 seconds and I could only find 1 answer for you I’m sorry

Andreas93 [3]3 years ago

4 0

Step-by-step explanation:

multiply length, width, and height

6x4x6 and 7x4x6

First line: <u>144cm</u>

Second line: <u>168cm</u>

and those are the answers

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Find the area of the shaded region please.

Ira Lisetskai [31]

The first shaded triangle is 144 cm.

7 0

3 years ago

The two triangles are similar. Which statements are true? Select each correct statement. ∠A≅∠D BDBA=DEAC BDBA=DEBC ∠B≅∠E Triangl

horsena [70]

Answer:

SR/BC=RT/CA And /R=/C S B And D

Step-by-step explanation:

Just Look at them then compare its pretty simple you just have to think about it.

5 0

3 years ago

A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4

skad [1K]

Answer:

a) $\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

b) The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got:

$\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

3 0

4 years ago

You have less than three hours to finish your homework which one of the following graphs represent the situation

vagabundo [1.1K]

There aren’t any graphs

3 0

3 years ago

PLEASE HELP ME!!!!!!

Nata [24]

9514 1404 393

Answer:

vertex: (2, -3.2)

axis of symmetry: x = 2

zeros: x=0, x=4

formula for axis of symmetry:

x = <x-coordinate of vertex>
x = -b/(2a) . . . . . . . where the quadratic is ax^2 +bx +c
x = average of zeros, (z1 +z2)/2

Step-by-step explanation:

a) The vertex x-coordinate is halfway between the zeros, so is x = (0+4)/2 = 2. It is where the graph has a turning point.

The vertex y-coordinate is the low point of this graph. It is not on a grid line, so we can only guess at its value. I choose to call it -3.2.

The vertex is (2, -3.2).

b) The axis of symmetry is the vertical line through the vertex. The constant in its equation is the x-coordinate of the vertex:

x = 2

c) The zeros of the function are where the function crosses the x-axis. These are marked on the graph with red dots. The zeros are x=0 and x=4.

d) When the quadratic is written in standard form, ax^2 +bx +c, the equation of the axis of symmetry is ...

x = -b/(2a) . . . . . perhaps this is the formula you're being asked for (?)

When there is no equation, the axis of symmetry can be found from the graph a couple of ways. One is to identify the x-coordinate of the vertex.

x = <x-coordinate of the vertex>

Another is to average the zeros, since they are symmetrical about the axis of symmetry.

x = average of zeros = (z1 +z2)/2

If the quadratic is written in vertex form, the vertex coordinate is the constant in the equation for the axis of symmetry.

y = a(x -h)^2 +k . . . . . quadratic with vertex (h, k)

x = h . . . . . . equation of axis of symmetry

8 0

3 years ago