The quadratic equation cannonball’s path if it was launched with the same velocity, but from the ground instead would be given by:
<h3>What is the quadratic equation for the height of a projectile?</h3>
Considering the gravity, it is modeled by:
In which:
is the initial velocity.
is the initial height.
For this problem, we want:
- The same initial velocity, hence
.
- Launched from the ground, hence
.
Then, the equation is:
More can be learned about quadratic equations at brainly.com/question/24737967
So anybody know the answer yet cuz i don’t
Answer:
56 i believe
Step-by-step explanation:
Answer: y = 2x
Step-by-step explanation:
The equation of a straight line can be represented in the slope intercept form as
y = mx + c
Where
m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)
The equation of the given line is
y = 2x - 8
Comparing with the slope intercept form, slope = 2
If two lines are parallel, it means that they have the same slope. Therefore, the slope of the line passing through (- 3,-6) is 2
To determine the intercept, we would substitute m = 2, x = - 3 and
y = - 6 into y = mx + c. It becomes
- 6 = 2 × - 3 + c
- 6 = - 6 + c
c = - 6 + 6 = 0
The equation becomes
y = 2x
