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3 years ago

What is the value of a when we rewrite 15^x as a^x/6

Mathematics

1 answer:

jarptica [38.1K]3 years ago

4 0

Answer:

a = 11,390,625.

Step-by-step explanation:

a^x/6 = (a^1/6)^x

(a^1/6)^x = 15^x so:

a^1/6 = 15

1/6 ln a = ln 15

ln a = 6 ln 15

ln a = 16.2483

a = 11390625.

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stellarik [79]

because you just eliminate it

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4 years ago

How to find the area of a circle

Vlad1618 [11]

Area of a circe = Pi x radius^2

6 0

1 year ago

Solve this linear system 28x + 44y = 964.40 21x + 33y = 723.30

Sladkaya [172]

28x + 44y = 964.40

21x + 33y = 723.30

Let's multiply the first equation by 4 and the second by -4

84x + 176y = 3857.6

-84x - 132y = -2893.2

Add the equations together.

0 + 44y = 964.4

Simplify

44y = 964.4

Divide both sides by 44

y = 964.4/44

Since we have the value of y, let's plug 964.4/44 into y for the first equation.

28x + 44(964.4/44) = 964.40

Simplify the left side

28x + 964.4 = 964.4

Subtract 964.4 from both sides

28x = 0

Divide both sides by 0

x = 0

In conclusion,

y = 964.4/44

x = 0

3 0

3 years ago

1. Given points A(3, -5) and B(19, -1), find the coordinates of point C that sit 3/8 of the way along line AB, closer to A than

zaharov [31]

1. C(x, y) = (7.3, –3.9)

2. C(x, y) = (17, –1.5)

Solution:

Question 1:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction $\frac{3}{8}$ .

Point divides segment in the ratio formula:

$$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)$

Here, $x_1=3, y_1=-5, x_2=19, y_2=-1$ and m = 3, n = 8

$$C(x, y)=\left(\frac{3\times19+8\times3}{3+8} , \frac{3\times(-1)+8\times(-5)}{3+8}\right)$

$$=\left(\frac{57+24}{11} , \frac{-3-40}{11}\right)$

$$=\left(\frac{81}{11} , \frac{-43}{11}\right)$

C(x, y) = (7.3, –3.9)

Question 2:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction $\frac{3}{8}$ .

Point divides segment in the ratio formula:

$$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)$

Here, $x_1=3, y_1=-5, x_2=19, y_2=-1$ and m = 7, n = 1

$$C(x, y)=\left(\frac{7\times19+1\times3}{7+1} , \frac{7\times(-1)+1\times(-5)}{7+1}\right)$

$$=\left(\frac{133+3}{8} , \frac{-7-5}{8}\right)$

$$=\left(\frac{136}{8} , \frac{-12}{8}\right)$

C(x, y) = (17, –1.5)

8 0

3 years ago

Find the 9th term of the geometric sequence 2, -10 50 -250

tigry1 [53]

Answer:

781250

Step-by-step explanation:

We first need to find the common ratio

-10 /2 = -5

50 / -10 = -5

The common ratio is -5

an = a (r) ^ (n-1)

a9 = 2 ( -5) ^(9-1)

= 2 (-5)^8

=781250

7 0

3 years ago