Question: If the subspace of all solutions of
Ax = 0
has a basis consisting of vectors and if A is a matrix, what is the rank of A.
Note: The rank of A can only be determined if the dimension of the matrix A is given, and the number of vectors is known. Here in this question, neither the dimension, nor the number of vectors is given.
Assume: The number of vectors is 3, and the dimension is 5 × 8.
Answer:
The rank of the matrix A is 5.
Step-by-step explanation:
In the standard basis of the linear transformation:
f : R^8 → R^5, x↦Ax
the matrix A is a representation.
and the dimension of kernel of A, written as dim(kerA) is 3.
By the rank-nullity theorem, rank of matrix A is equal to the subtraction of the dimension of the kernel of A from the dimension of R^8.
That is:
rank(A) = dim(R^8) - dim(kerA)
= 8 - 3
= 5
Ex.
f + g = y
-----------
3
3(f+g) = (y) 3
--------
3
f + g =3y
f - f + g = 3y - f
g = y - f
I don’t know I’m only in 7th grade but 56
Answer:
Circle B area = 49π square units
Step-by-step explanation:
Circle A radius =√25 = 5 units
(1.2)(5) = 7 = radius circle B
Circle B area = 7²π = 49π square units
Step-by-step explanation:
The second one is the first claim, because it is a traingles and one square.
The third one is the sond claim because they are a part of the rectangular so moving them outside of it would increase the area, I think, if that makes sense.
