The act of using computer equipment to “break into” the computer systems of others?

Computers and Technology

1 answer:

zlopas [31]2 years ago

3 0

Answer:

Hacking.

Explanation:

Breaking into other systems sounds like hacking.

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Web analytical packages can obtain the following information when someone visits a website, except Group of answer choices name

il63 [147K]

Answer:

name and address of web visitors.

Explanation:

A website refers to the collective name used to describe series of web pages linked together with the same domain name.

Web analytical packages are software features that are typically used for tracking the identity of a computer system by placing or adding cookies to the computer when it's used to visit a particular website. Thus, it's only used for tracking the identity of a computer but not the computer users.

This ultimately implies that, web analytical packages can obtain the geographic location, Internet connection type, and navigation source information when someone visits a website, but it cannot obtain the name and address of web visitors or users.

3 0

2 years ago

. (a) Prove or disprove carefully and in detail: (i) Θ is transitive and (ii) ω is transitive. (b) Assume n is a positive intege

Sergio [31]

Answer:

The Following are the solution to this question:

Explanation:

In Option a:

In the point (i) $\Omega$ is transitive, which means it converts one action to others object because if $\Omega(f(n))=g(n)$ indicates $c.g(n)$ . It's true by definition, that becomes valid. But if $\Omega(g(n))=h(n)$ , which implies $c.h(n)$ . it's a very essential component. If $c.h(n) < = g(n) = f(n) \$ . They $\Omega(f(n))$ will also be $h(n)$ .

In point (ii), The value of $\Theta$ is convergent since the $\Theta(g(n))=f(n)$ . It means they should be dual a and b constant variable, therefore $a.g(n)$ could only be valid for the constant variable, that is $\frac{1}{a}\ \ and\ \ \frac{1}{b}$ .

In Option b:

In this algorithm, the input size value is equal to 1 object, and the value of A is a polynomial-time complexity, which is similar to its outcome that is $O(n^{2})$ . It is the outside there will be a loop(i) for n iterations, that is also encoded inside it, the for loop(j), which would be a loop $(n^{2})$ . All internal loops operate on a total number of $N^{2}$ generations and therefore the final time complexity is $O(n^{2})$ .