All categories

2 years ago

If two triangles are congruent, which of the following statements must be

Mathematics

2 answers:

Burka [1]2 years ago

7 0

Answer:

[A] The corresponding sides of the triangles are congruent.

[B] The corresponding angles of the triangles are congruent.

[C] The triangles have the same size.

[D] The triangles have the same shape.

Step-by-step explanation:

SAS which it is stands for {side, angle, side} and the meaning of SAS is that we have two triangles where we see two sides and the included angle are equal.

In Order for two triangles to be congruent must have the following below:

Two figures are said to be congruent if they have same size and same shape.
If two figure are congruent that means the corresponding sides will also be congruent.
If two figure are congruent that means the the corresponding angles will also be congruent.

Hence, base on the given all the following are correct:

A. The corresponding sides of the triangles are congruent. √

B. The corresponding angles of the triangles are congruent. √

C. The triangles have the same size. √

D. The triangles have the same shape. √

Kavinsky

kenny6666 [7]2 years ago

7 0

Answer:

Step-by-step explanation:

b/c the sides are corresponding and corresponding angles are always equal

You might be interested in

Simplify if possible

Anarel [89]

The answer is the last choice 2 1/2

8 0

3 years ago

Read 2 more answers

X-4y =-6 ( ,2) (-2, )

marin [14]

Answer:5x-20y=12

Step-by-step explanation:

5 0

3 years ago

10 x 3 tens in standard form?

Lubov Fominskaja [6]

10 x 30=300 because you 3 tens is 30 times 10 is 300. hope it helped.

6 0

3 years ago

Need help with this confusing

Dahasolnce [82]

Answer:

The blanks are 18 and 20

equivalent ratios

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Which equation has the solutions x = -3 ± √3i/2 ?

Maurinko [17]

Answer:Answer is option C : [ $x^{2}$ + 3x + 3 ] =0

Note: None of options matches with given question.

instead of "-3" , there should be "- $\frac{3}{2}$ ".

Step-by-step explanation:

Note: None of options matches with given question.

instead of "-3" , there should be " $\frac{3}{2}$ ".

Here, First thing you have to observe the nature of roots.

∴ x = - $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i and x = - $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$

∴ [ x+( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) ][ x+( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + x( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i)+ x( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + $\frac{3}{2}$ x + $\frac{\sqrt{3}}{2}$ ix + $\frac{3}{2}$ x - $\frac{\sqrt{3}}{2}$ ix + (3- $\frac{\sqrt{3}}{2}$ i)(3+ $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{\sqrt{3}}{2}$ i)( $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{3}{4}$ ) $i^{2}$ ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ + ( $\frac{3}{4}$ ) ] =0

∴ [ $x^{2}$ + 3x + $\frac{12}{4}$ ] =0

∴ [ $x^{2}$ + 3x + 3 ] =0

Thus, Answer is option C : [ $x^{2}$ + 3x + 3 ] =0

6 0

4 years ago