So ive done the math and if you add both mA & mB , mC would equal 10
 
        
             
        
        
        
Step-by-step explanation:
ED is greater than BC
the line from B to ED ^ (which i drew ) the point it touches ED name it X. so EX will be 2 ( ED-BC)(6-4). 
then u have a triangle. EX, XB and EB.
you have length of EX(2) and u have hypotenuse. so u can calculate XB using Pythagoras theorem. 
15.1²=2²+XB²
15.1²-2²=XB²
224.01=XB²
XB=14.97
since XB and DC are parallel ( a rectangle is forming XBCD) so DC is also 14.97
 
        
             
        
        
        
Answer:
The one with arrows are the answers
->Line segment E B  is bisected by Line segment D F .
->A is the midpoint of Line segment F C .
Line segment F C  bisects Line segment D B.
->Line segment E B  is a segment bisector.
->FA = One-halfFC.
Line segment D A is congruent to Line segment A B .
Step-by-step explanation:
I did it on edge and got it right
 
        
                    
             
        
        
        
Answer:
dependent
Step-by-step explanation:
These two events are dependent.  When the ball is set aside, there are fewer balls  to draw from, so the probability of getting a certain ball becomes greater.