What is the midpoint of the line segment with endpoints (-5.5 -6.1) and (-0.5 9.1)?
1 answer:
You might be interested in
Refer to the image for the graph of the lines.
The common form of the equation of a line is y = mx + c, where m is the slope of the line and c is a constant.
We need to draw any line with a slope m = 2, and
another line with a slope m = -2.
Disclaimer: Let us assume that the constant c = 0.
Then the equation to the line with a slope of "positive" 2 is given by
y = 2x
Then the equation to the line with a slope of "negative" 2 is given by
y = -2x
Refer to the attached image for the graph of the lines with the slope of "positive" 2 and "negative" 2.
f: green line indicates a line with a slope of "positive" 2.
g: blue line indicates a line with a slope of "negative" 2.
Learn more at:
#SPJ9
Answer:
See below
Step-by-step explanation:
(a) Field lines
A negatively charged particle has an electric field associated with it.
The field lines spread out radially from the centre of the point. They are represented by arrows pointing in the direction that a positive charge would move if it were in the field.
Opposite charges attract, so the field lines point toward the centre of the particle.
For an isolated negative particle, the field lines would look like those in Figure 1 below.
If two negative charges are near each other, as in Figure 2, the field lines still point to the centre of charge.
A positive charge approaching from the left is attracted to both charges, but it moves to the closer particle on the left.
We can make a similar statement about appositive charge approaching from the left.
Thus, there are few field lines in the region between the two particles.
(b) Coulomb's Law
The formula for Coulomb's law is
F = (kq₁q₂)/r²
It shows that the force varies inversely as the square of the distance between the charges.
Thus, the force between the charges decreases rapidly as they move further apart.
