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Marianna [84]
2 years ago
5

Which improper fraction is equivalent to 17.8? 89/10 93/10 89/5

Mathematics
2 answers:
Alchen [17]2 years ago
5 0

Answer:

17.8.

Step-by-step explanation:

89/5

= 17 4/5

= 17.8.

dedylja [7]2 years ago
4 0

Answer:

89/5

Step-by-step explanation:

17.8

To make this a faction

178/10

Divide by 2 on top and bottom

89/5

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Rewrite the sentence with correct punctuation and capitalization.
Ludmilka [50]
Matthew bought his cat, Filmore, at Mr. Macintosh’s pet store in Lincoln, Nebraska. (could do “!” at the end too)
7 0
3 years ago
You sold 500 shares of Intel for $26.75 per share. Your broker charges you a
Natali [406]

Answer: $13339.25

Step-by-step explanation:

Since 500 shares of Intel were sold for $26.75 per share, the total amount will be:

= 500 × $26.75

= $13375

Since the broker charges a

commission of $2.75 per thousand dollars of stock bought or sold, the amount charged by the broker on $13375 will be:

= $2.75 × 13

= $35.75

The amount that'll then be credited into ones account will be:

= $13375 - $35.75

= $13339.25

8 0
3 years ago
Observe os pontos Z, Y, W, X e V marcados na reta numérica abaixo.
adelina 88 [10]

Y

A raiz quadrada de 14 seria 3.74165738677 ou 3.7

Arredondamos para 4 já q 7 é próximo de 10

5 0
3 years ago
The question is find x
Allushta [10]

Answer:

x = 8

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

\frac{BC}{EF} = \frac{CD}{FG}

Note that ΔBCD is a 3- 4- 5 triangle ( Pythagorean triple), hence CD = 4

Substitute given values into the equation

\frac{3}{6} = \frac{4}{x} ( cross- multiply )

3x = 24 ( divide both sides by 3 )

x = 8

8 0
3 years ago
For integers a, b, and c, consider the linear Diophantine equation ax C by D c: Suppose integers x0 and y0 satisfy the equation;
Dmitrij [34]

Answer:

a.

x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )

b. x = -8 and y = 4

Step-by-step explanation:

This question is incomplete. I will type the complete question below before giving my solution.

For integers a, b, c, consider the linear Diophantine equation

ax+by=c

Suppose integers x0 and yo satisfy the equation; that is,

ax_0+by_0 = c

what other values

x = x_0+h and y=y_0+k

also satisfy ax + by = c? Formulate a conjecture that answers this question.

Devise some numerical examples to ground your exploration. For example, 6(-3) + 15*2 = 12.

Can you find other integers x and y such that 6x + 15y = 12?

How many other pairs of integers x and y can you find ?

Can you find infinitely many other solutions?

From the Extended Euclidean Algorithm, given any integers a and b, integers s and t can be found such that

as+bt=gcd(a,b)

the numbers s and t are not unique, but you only need one pair. Once s and t are found, since we are assuming that gcd(a,b) divides c, there exists an integer k such that gcd(a,b)k = c.

Multiplying as + bt = gcd(a,b) through by k you get

a(sk) + b(tk) = gcd(a,b)k = c

So this gives one solution, with x = sk and y = tk.

Now assuming that ax1 + by1 = c is a solution, and ax + by = c is some other solution. Taking the difference between the two, we get

a(x_1-x) + b(y_1-y)=0

Therefore,

a(x_1-x) = b(y-y_1)

This means that a divides b(y−y1), and therefore a/gcd(a,b) divides y−y1. Hence,

y = y_1+r(\frac{a}{gcd(a, b)})  for some integer r. Substituting into the equation

a(x_1-x)=rb(\frac{a}{gcd(a, b)} )\\gcd(a, b)*a(x_1-x)=rba

or

x = x_1-r(\frac{b}{gcd(a, b)} )

Thus if ax1 + by1 = c is any solution, then all solutions are of the form

x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )

In order to find all integer solutions to 6x + 15y = 12

we first use the Euclidean algorithm to find gcd(15,6); the parenthetical equation is how we will use this equality after we complete the computation.

15 = 6*2+3\\6=3*2+0

Therefore gcd(6,15) = 3. Since 3|12, the equation has integral solutions.

We then find a way of representing 3 as a linear combination of 6 and 15, using the Euclidean algorithm computation and the equalities, we have,

3 = 15-6*2

Because 4 multiplies 3 to give 12, we multiply by 4

12 = 15*4-6*8

So one solution is

x=-8 & y = 4

All other solutions will have the form

x=-8+\frac{15r}{3} = -8+5r\\y=4-\frac{6r}{3} =4-2r

where r ∈ Ζ

Hence by putting r values, we get many (x, y)

3 0
3 years ago
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