Either way. The probability of hitting the circle is:
P(C)=Area of circle divided by area of square
P(W)=(area of square minus area of circle divided by area of square
P(C)=(πr^2)/s^2
P(W)=(s^2-πr^2)/s^2
...
Okay with know dimensions, r=1 (because r=d/2 and d=2 so r=1), s=11 we have:
P(inside circle)=π/121 (≈0.0259 or 2.6%)
P(outside circel)=(121-π)/121 (≈0.9744 or 97.4%)
Wouldn't the formula be a×b/2?
solution
1) <span>Expand
</span><span>9x−6−12x
2) </span><span>Gather like terms
</span><span>(9x−12x)−6
3) </span> <span>Simplify
</span><span><span>−3x−6</span></span>
Answer:
why does it say answer doesn't exist but still lemme put a answer
