Solution:
Given:
To determine if an ordered pair is a solution, we substitute the x and y-values into the inequality and check if it is true.
Thus,
Therefore, the correct answers are selected as shown below;
The first one and the last one, the 2 middle ones are not corresponding
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
Answer:
-3
Step-by-step explanation:
Because f(x) = y so when y=3 what is input value (x)
When y is 3 x is -3
You set (x+15) equal to 40 and solve for x.
x+15=40
-15 -15
x=25
Hope this helps!
